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3 years ago

What the Answer please?

Mathematics

1 answer:

Brrunno [24]3 years ago

8 0

Answer:

x = 151

Step-by-step explanation:

In the figure given, x is an exterior angle of the ∆.

According to the exterior angle theorem, x = the sum of the two opposite interior angles of the ∆.

One of the opposite angles measures 101°, while the second opposite angle equal 50°, since line l is parallel to m, alternate interior angles are equal.

Therefore, x = 101 + 50 = 151°

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myrzilka [38]

Here is the anwser to the problem

6 0

3 years ago

I need help asap with this

tatyana61 [14]

Answer:

51°

Step-by-step explanation:

Given

<QPR = 39°

<PQR = 90° ( inscribed angle in semi circle)

Now

<QPR + <PQR + <PRQ = 180° { being sum of angles of triangle)

39° + 90° + <PRQ = 180°

<PRQ = 180° - 39° - 90°

<PRQ = 51°

Hope it will help :)

5 0

3 years ago

EXPERTS/ACE/TRUSTED HELPERS

SVETLANKA909090 [29]

ST and WX are the same lines

4 0

3 years ago

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Which of the following relationships is a direct variation?

mafiozo [28]

Answer:Well All i know is that the answer is not C I'm sorry I dont know the correct answer but I know for a fact that the answer isn't C

Step-by-step explanation:

4 0

3 years ago

In the game of blackjack played with one deck, a player is initially dealt 2 different cards from the 52 different cards in the

Volgvan

Answer:

$P =4.83\%$

Step-by-step explanation:

First we calculate the number of possible ways to select 2 cards an ace and a card of 10 points.

There are 4 ace in the deck

There are 16 cards of 10 points in the deck

To make this calculation we use the formula of combinations

$nCr=\frac{n!}{r!(n-r)!}$

Where n is the total number of letters and r are chosen from them

The number of ways to choose 1 As is:

$4C1 = 4$

The number of ways to choose a 10-point letter is:

$16C1 = 16$

Therefore, the number of ways to choose an Ace and a 10-point card is:

$4C1 * 16C1 = 4 * 16 = 64$

Now the number of ways to choose any 2 cards from a deck of 52 cards is:

$52C2 =\frac{52!}{2!(52-2)!}$

$52C2 = 1326$

Therefore, the probability of obtaining an "blackjack" is:

$P = \frac{4C1 * 16C1}{52C2}$

$P = \frac{64}{1326}$

$P = \frac{32}{663}$

$P =0.0483$

$P =4.83\%$

4 0

3 years ago

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