Answer:
Step-by-step explanation:
S=student cost; T=teacher cost
.
32S+3T=$127 . Multiply this by 2.
64S+6T=$254 Subtract this below
.
25S+2T=$97.50 . Multiply this by 3.
75S+6T=$292.50
64S+6T=$254 . Subtract this (from above.)
.
11S=$38.50
S=$3.50
ANSWER 1: Student tickets cost $3.50.
.
32S+3T=$127
32($3.50)+3T=$127
$112+3T=$127
3T=$15
T=$5.00
ANSWER 2: Teacher tickets cost $5.00.
.
CHECK:
25S+2T=$97.50
25($3.50)+2($5.00)=$97.50
$87.50+$10.00=$97.50
$97.50=$97.50
Answer: C. 6
Step-by-step explanation:
Given : Time taken by Machine R to do the job = 36 hours
Time taken by Machine S to do the job = 18 hours
Let x be the number of each type of machine to do the job.
Then , according to the question the required equation will be :-
Hence, the number of machines of type R were used =6
Answer:
the baser to their question would be 2 since its lined up and thrn it would be 4
62.50/5=12.50 for each tour
500/12.50 = 40 tours
Graph the feasible region for the following constraints: x + y < 5. 2x + y > 4 ... y = 10/3. x = 30/3 - 10/3 = 20/3. Intersects at (20/3, 10/3). -x + 2y = 0. x - 2y = 0.
hence i would go for
<span>(6,3)</span>
