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2 years ago

Angle 1 is vertical to Angle 2. Angle 1 =94, Angle 2 = 2(x-13), Find the value of x.

Mathematics

1 answer:

rodikova [14]2 years ago

4 0

Answer:

x= 56

Step-by-step explanation:

86+94= 180 which if supplementary angles have to equal 180°

I don't know if you can tell but what's in red means distribute

then I added 26 on both sides with like terms

on the left side 86+26=112 and right side is left with 2x

then divide both sides by 2 to leave x by itself

112/2= 56 and 2x/2=x

so 56=x

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Let v1=(2,-6) and v2=(-4,7)

seropon [69]

The magnitude of each vector is the Pythagorean sum of its components.

a. |v1| = √(2² + (-6)²) = √40 = 2√10

|v2| = √((-4)² + 7²) = √65

b. To make each vector into a unit vector, divide each component by the vector's magnitude.

u1 = v1/|v1| = (2/(2√10), -6/(2√10))

u1 = (√10/10, -3√10/10)

u2 = v2/|v2| = (-4/√65, 7/√65)

u2 = (-4√65/65, 7√65/65)

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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andrey2020 [161]

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2 years ago

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Becky, an artist, plans to paint and sell some miniature paintings. She just bought some brushes for $1, and paint and canvas fo

Veronika [31]

Answer:

After one unit is sold, Becky will break-even.

Step-by-step explanation:

Giving the following information:

Fixed costs= $1

Unitary variable cost= $21

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2 years ago

If the demand function for a commodity is given by the equation

Jet001 [13]

Answer:

q=26.92 p=31.13

Step-by-step explanation:

$p^{2} +16q=1400\\\\q=\frac{1400-p^{2} }{16} ;\\\\700-p^{2} +10q=0\\\\q=\frac{p^{2}-700 }{10} ;\\\\$

$q=q\\\\\frac{1400-p^{2} }{16} =\frac{p^{2}-700 }{10} \\\\10(1400-p^{2})=16(p^{2}-700)\\\\14000-10p^{2}=16p^{2}-11200\\\\14000+11200=16p^{2}+10p^{2}\\\\25200=26p^{2}\\\\p^{2}=\frac{25200}{26} \\\\p=+\sqrt{\frac{25200}{26}} \\\\p=31.13$

replace p in any equation and

$q=\frac{1400-p^{2} }{16} \\\\q=\frac{1400-(31.13)^{2} }{16}\\\\q=26.92$

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3 years ago