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LenaWriter [7]
3 years ago
10

What is the difference between points F (2,9) and G (4,14) round to the nearest whole number.

Mathematics
1 answer:
Sonbull [250]3 years ago
7 0

Answer:

3,15

Step-by-step explanation:

took the test boi

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Tire pressure monitoring systems (TPMS) warn the driver when the tire pressure of the vehicle is 26% below the target pressure.
lesya692 [45]

Answer:

(a) At 21.46 psi, the TPMS trigger a warning for this car.

(b) The probability that the TPMS will trigger a warning is 0.0001.

(c) The probability that the tire’s inflation is within the recommended range is 0.6826.

Step-by-step explanation:

We are given that tire pressure monitoring systems (TPMS) warn the driver when the tire pressure of the vehicle is 26% below the target pressure. Suppose the target tire pressure of a certain car is 29 psi (pounds per square inch).

(a) It is stated that TPMS warns the driver when the tire pressure of the vehicle is 26% below the target pressure.

So, the TPMS trigger a warning for this car when;

Pressure = 29 psi - 26% of 29 psi

               = 29-(0.26 \times 29)  = 21.46 psi

At 21.46 psi, the TPMS trigger a warning for this car.

(b) Suppose tire pressure is a normally distributed random variable with a standard deviation equal to 2 psi.

Let X = <u><em>The pressure at which TPMS will trigger a warning</em></u>

So, X ~ Normal(\mu=29, \sigma^{2} =2^{2})

Now, the probability that the TPMS will trigger a warning is given by = P(X \leq 21.46)

        P(X \leq 21.46) = P( \frac{X-\mu}{\sigma} \leq \frac{21.46-29}{2} ) = P(Z \leq -3.77) = 1 - P(Z < 3.77)

                                                              = 1 - 0.9999 = <u>0.0001</u>

The above probability is calculated by looking at the value of x = 3.77 in the z table which has an area of 0.9999.

(c) The manufacturer’s recommended correct inflation range is 27 psi to 31 psi.

So, the probability that the tire’s inflation is within the recommended range is given by = P(27 psi < X < 31 psi)

     P(27 psi < X < 31 psi) = P(X < 31 psi) - P(X \leq27 psi)

     P(X < 31 psi) = P( \frac{X-\mu}{\sigma} < \frac{31-29}{2} ) = P(Z < 1) = 0.8413

     P(X \leq 27 psi) = P( \frac{X-\mu}{\sigma} \leq \frac{27-29}{2} ) = P(Z \leq -1) = 1 - P(Z < 1)

                                                        = 1 - 0.8413 = 0.1587

Therefore, P(27 psi < X < 31 psi) = 0.8413 - 0.1587 = <u>0.6826</u>.

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-$67 represents the greatest change
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It's an acute angle because it's smaller than 90 degrees and isn't a straight line.

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