Answer:
A. (3,1)
B. g(x)=|x-3|+6
C. h(x)=-|x-3|-6
Step-by-step explanation:
A. To graph the absolute value function f(x) = |x - 3| + 1, first graph the parent absolute value function y=|x| and then translate it 3 units to the right and 1 unit up (see green graph in attached diagram). The vertex of the function f(x) is at point (3,1).
B. The function g(x) translates f(x) 5 units up, so its equation is
g(x)=f(x)+5
g(x)=|x-3|+1+5
g(x)=|x-3|+6
Blue graph in attached diagram.
C. The function h(x) reflects g(x) over the x-axis, so the equation of the function h(x) is
h(x)=-g(x)
h(x)=-(|x-3|+6)
h(x)=-|x-3|-6
Red graph in attached diagram.
Answer:
T = 2
Step-by-step explanation:
Take the given formulaer
I = PRT
And plug in the variables you know (I, P, R)
387.50 = 1,550(.125)T
(12.5% becomes .125 after you divide it by 100, because precents are really just fractions out of 100)
387.50 = 193.75T
T = 2
Answer:
Y=-4x+6
Step-by-step explanation:
Step 1: Add -x to both sides.
X+0.25y+-x=1.5+-x
0.25y=-x+1.5
Step 2: Divide both sides by 0.25.
0.25y/0.25=-x+1.5/0.25
Y=-4x+6
Hope I helped
9514 1404 393
Answer:
1. ∠EDF = 104°
2. arc FG = 201°
3. ∠T = 60°
Step-by-step explanation:
There are a couple of angle relationships that are applicable to these problems.
- the angle where chords meet is half the sum of the measures of the intercepted arcs
- the angle where secants meet is half the difference of the measures of the intercepted arcs
The first of these applies to the first two problems.
1. ∠EDF = 1/2(arc EF + arc UG)
∠EDF = 1/2(147° +61°) = 1/2(208°)
∠EDF = 104°
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2. ∠FHG = 1/2(arc FG + arc ES)
128° = 1/2(arc FG +55°) . . . substitute given information
256° = arc FG +55° . . . . . . multiply by 2
201° = arc FG . . . . . . . . . subtract 55°
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3. For the purpose of this problem, a tangent is a special case of a secant in which both intersection points with the circle are the same point. The relation for secants still applies.
∠T = 1/2(arc FS -arc US)
∠T = 1/2(170° -50°) = 1/2(120°)
∠T = 60°
