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GuDViN [60]
3 years ago
12

Please help with these questions

Mathematics
1 answer:
Elis [28]3 years ago
6 0
Obviously, what you looking for is slopes. Now let's get started. 
6.) 7x-5y=20 You subtract 7x both sides.
    -7x      -7x
-5y=-7x+20  Then you divide -5 both sides (which is include -7 and 20).
y=7/5x-4 Simplify.
-8x-3y=12 Add 8x both sides because it's a negative number.
+8x    +8x
-3y=8x+12 Divide -3 both sides.
y=-8/3x-4 Simplify.
 And your point value is (0,-4).
7.) -x-4y=12 Add x both sides.
     +x     +x
-4y=x+12 Divide -4 both sides.
y=-1/4x-3 Simplify.
20x+80y=0 Subtract 20x both sides.
-20x      -20x
80y=-20x Divide 80 both sides. Here's a hint: 20/80 is same thing as 2/8, so 
                you don't have to do all that. 
y=1/4x Simplify. Here's another hint: I bet you wondering there's no y-                         intercept. The y-intercept is (0,0).
Both of the functions are parallel, so there's no solution. 
8.) 30x+50y-100=0 Add 100 both sides.
                +100  +100
30x+50y=100 Subtract 30x both sides. 
-30x       -30x
50y=-30x+100 Divide 50 both sides.
y=-3/5x+2 Simplify.
3x-15y-30=0 Add 30 both sides.
          +30 +30
3x-15y=30 Subtract 3x both sides.
-3x      -3x
-15y=-3x+30 Divide -15 both sides.
y=1/5x-2 Simplify.
And your point value is (5,-1).
I hope it helps.
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Read 2 more answers
At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper
Korvikt [17]

Answer:

90.67% probability that John finds less than 7 golden sheets of paper

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it contains a golden sheet of paper, or it does not. The probability of a container containing a golden sheet of paper is independent of other containers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper containers.

This means that p = 0.3

14 of these containers of paper.

This means that n = 14

What is the probability that John finds less than 7 golden sheets of paper?

P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{14,0}.(0.3)^{0}.(0.7)^{14} = 0.0068

P(X = 1) = C_{14,1}.(0.3)^{1}.(0.7)^{13} = 0.0407

P(X = 2) = C_{14,2}.(0.3)^{2}.(0.7)^{12} = 0.1134

P(X = 3) = C_{14,3}.(0.3)^{3}.(0.7)^{11} = 0.1943

P(X = 4) = C_{14,4}.(0.3)^{4}.(0.7)^{10} = 0.2290

P(X = 5) = C_{14,5}.(0.3)^{5}.(0.7)^{9} = 0.1963

P(X = 6) = C_{14,6}.(0.3)^{6}.(0.7)^{8} = 0.1262

P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0068 + 0.0407 + 0.1134 + 0.1943 + 0.2290 + 0.1963 + 0.1262 = 0.9067

90.67% probability that John finds less than 7 golden sheets of paper

7 0
3 years ago
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