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bogdanovich [222]
3 years ago
7

Type the correct answer in each box.

Mathematics
2 answers:
Fittoniya [83]3 years ago
8 0

the answer would be 2.5

Oduvanchick [21]3 years ago
4 0

Answer:

the real answer -1/3 1/3

Step-by-step explanation:

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Help with math homework pls!
Svetach [21]

the correct answer is a^6


5 0
3 years ago
Chase goes out to lunch. The bill, before tax and tip, was $11.90. A sales tax of 9% was added on. Chase tipped 17% on the amoun
WINSTONCH [101]

Answer:

$15.17

Step-by-step explanation:

First we calculate the value for the sales tax:

11.90 \times  \frac{9}{100 }  = 1.07

we then add the value for the sales tax ($1.07) to the initial bill:

11.90 + 1.07 = 12.97

We were instructed to calculate the tip after the sales tax was added so:

12.97 \times  \frac{17}{100}  = 2.20

after we will add the value for the tip to the value that we have for the bill ( this is the new value that includes the sales tax) to find the total cost:

12.97+ 2.20  = 15.17

<em>Therefore</em><em> </em><em>the</em><em> </em><em>total</em><em> </em><em>cost</em><em> </em><em>for</em><em> </em><em>his</em><em> </em><em>mean</em><em> </em><em>is</em><em> </em><em>$</em><em>15.17</em>

4 0
2 years ago
14. Find mZCDB.<br> B<br> С<br> 18<br> 7<br> D<br> 47°<br> А A
Anna [14]

Answer:

n,

Step-by-step explanation:

n

8 0
3 years ago
Jina's dance recital started at 4:46 PM. It ended at 6:13 PM. How long did the recital last?
Tamiku [17]

Answer:

Jina's recital lasted 2 hours and 7 minutes

Hope that helped

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
An object launched straight up at a speed of 29.4 meters per second has a height, h, in meters of h , t seconds after the object
Nostrana [21]

Answer:

h = 44.06 meters (maximum height)

the time the object takes to complete this whole path is 6 seconds, this is why the time at which the object reaches its maximum height will between 0 and 6 seconds

Step-by-step explanation:

To solve this question, we need to first recognize that this is a constant acceleration problem, specifically, it can be thought of as a projectile motion problem.

Recall, the equations of motion:

1) v^2 - v_0^2 = 2a(s - s_0)\\2) s = v_0^2  + \frac{1}{2} at^2\\3) v = v_0 + at

What do we already know?

  • v_0 = 29.4 ms^-1
  • The launch is straight up
  • a = -9.81 ms^-2 this is the gravitational acceleration g
  • s_0 = 0 m, since our reference point is at s = 0, (the ground)

We can use use the Eq(1):

we know that when any object is launched up, at maximum height its velocity is going to be zero, v = 0 ms^-2

v^2 - v_0^2 = 2a(s - s_0)\\0^2 - (29.4)^2 = 2(-9.81)(s- 0)\\s = 44.06 m

this is the maximum height!

Why does t have to between zero and six?

We can answer this using a bit visualization, if you think about the second equation

s = v_0 t - \frac{1}{2}at^2\\ s = 29.4t - 4.905t^2

this is the equation of the whole trajectory that object makes.

and if you solve this by making s = 0, you will get the times at which the object was at the ground. the times will be 0s and 5.99s.

so the amount of time the object takes to go through this whole path is 6 seconds and this why the object will only reach its maximum height in between this time interval.

hope this helps :)

5 0
3 years ago
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