X=6 and x=1
You can find your zeros by determining what you have to plug into the function in order for it to equal zero
If we plug in 6, for example we’d get (6-6)(x-1)
Simplified this is 0(x-1)
Anything times 0 is 0, so this is one of our zeros.
Same goes for x-1, we just need to plug in 1 for it to equal 0
Therefore there are zeros at x=1 and x=6 :))
Answer:
P(5, 1)
Step-by-step explanation:
Segment AB is to be partitioned in a ratio of 5:3. That means the ratio of the lengths of AP to PB is 5:3. We need to find the ratio of the lengths of AP to AB.
AP/PB = 5/3
By algebra:
PB/AP = 3/5
By a rule of proportions:
(PB + AP)/AP = (3 + 5)/5
PB + AP = AP + PB = AB
AB/AP = 8/5
AP/AB = 5/8
The first part of the segment is 5/8 of the length of the segment, and the second part of the segment has length of 3/8 of the length of segment AB.
Point P is located 5/8 of the distance from point A to point B. The x-coordinate of point P is 5/8 of the difference in x-coordinates added to the x-coordinate of point A. The y-coordinate of point P is 5/8 of the difference in y-coordinates added to the y-coordinate of point A.
x-coordinate:
difference in coordinates: |14 - (-10)| = |14 + 10| = 24
5/8 of 24 = 5/8 * 24 = 15
Add 15 to the x-coordinate of point A: -10 + 15 = 5
x-coordinate of point P: 5
y-coordinate:
difference in coordinates: |4 - (-4)| = |4 + 4| = 8
5/8 of 8 = 5/8 * 8 = 5
Add 5 to the y-coordinate of point A: -4 + 5 = 1
y-coordinate of point P: 1
Answer: P(5, 1)
Answer:
10/3 minutes
Step-by-step explanation:
12 minutes to run 6 times is the same as 2 minutes to run once (ratios)
so it takes 2 minutes to run once around a 600 m track
so 2 minutes/600m = x minutes/1000m
x = 2/600 * 1000 = 20/6 = 10/3
First you have to divide the 9 on both sides to get x alone. Next you would have to divide 117 and 9. (117÷9=13) . So x>13
