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ZanzabumX [31]
3 years ago
5

GUYS PLS HELP ME ITZ MY LAST ASSIGNMENT I NEED AND I DONT KNOW HOW TO DO ITTTT

Mathematics
2 answers:
poizon [28]3 years ago
5 0

<em><u>Look</u></em><em><u> </u></em><em><u>at</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>attached</u></em><em><u> </u></em><em><u>picture</u></em><em><u>⤴</u></em>

<em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>help</u></em><em><u> </u></em><em><u>u</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

trasher [3.6K]3 years ago
4 0

Answer:

2hich one

Step-by-step explanation:

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Select the three expressions that are equivalent to 2 (4 - 3x) + (5x-2) ​
Ivanshal [37]

Answer:

The answer correct the questions is 11x-10

4 0
3 years ago
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Find the probability of rolling an odd sum or a sum less than 7 when a pair of dice is rolled
Nutka1998 [239]

Answer:

For the pairs that satisfy that the sum is less than 7 we have:

(1,1) (2,1) (1,2) (3,1) (2,2) (1,3) (4,1) (3,2) (2,3) (1,4) (5,1) (4.2) (3,3) (2,4) (1,5)

So we have a total of 15 pairs where the sum is less than 7

And for an odd sum we have the following pairs

(2,1) (1,2) (4,1) (3,2) (2,3) (1,4) (6,2) (5,2) (4,3) (3,4) (2,5) (1,6) (6,3) (5,4) (4,5) (3,6) (6,5) (5,6)

A total of 18 pairs and we have 6 pairs who are in both cases for the sum less than 7 and the sum an odd number that represent the intersection and using the total probability rule we got:

P = \frac{15+18-6}{36}= \frac{27}{33}= 0.818

Step-by-step explanation:

For this case when a pair of dice is rolled we have the following sample pace for the outcomes:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

We see 36 possible outcomes and we want to find how many of these pairs we got rolling an odd sum or a sum less than 7

For the pairs that satisfy that the sum is less than 7 we have:

(1,1) (2,1) (1,2) (3,1) (2,2) (1,3) (4,1) (3,2) (2,3) (1,4) (5,1) (4.2) (3,3) (2,4) (1,5)

So we have a total of 15 pairs where the sum is less than 7

And for an odd sum we have the following pairs

(2,1) (1,2) (4,1) (3,2) (2,3) (1,4) (6,2) (5,2) (4,3) (3,4) (2,5) (1,6) (6,3) (5,4) (4,5) (3,6) (6,5) (5,6)

A total of 18 pairs and we have 6 pairs who are in both cases for the sum less than 7 and the sum an odd number that represent the intersection and using the total probability rule we got:

P = \frac{15+18-6}{36}= \frac{27}{33}= 0.818

7 0
3 years ago
Hey i am not smart but what is <br> <img src="https://tex.z-dn.net/?f=83%5Cfrac%7B1%7D%7B3%7D%20minus%20%5Cfrac%7B2%7D%7B3%7D" i
Ray Of Light [21]
It would be 82 2/3 since 1/3 minis 2/3 would equal -1/3 you subtract that from 83 and get 82 2/3
6 0
3 years ago
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If a 9-foot flagpole casts a 6-foot shadow, how tall is the woman who casts a 4-foot shadow?
FinnZ [79.3K]
It is A because if you subtract 9 and 6 you get 3 and then you add the 4 and get 7
6 0
3 years ago
Solve the system of equations. y = x − 5 and y = x2 − 5x + 3 A. (-4,-9) and (-2,-7) B. (4,-9) and (2,-7) C. (4,-3) and (2,-1) D.
larisa [96]

Answer:

D

Step-by-step explanation:

Given the 2 equations

y = x - 5 → (1)

y = x² - 5x + 3 → (2)

Substitute y = x² - 5x + 3 into (1)

x² - 5x + 3 = x - 5 ← subtract x - 5 from both sides

x² - 6x + 8 = 0 ← in standard form

(x - 2)(x - 4) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 2 = 0 ⇒ x = 2

x - 4 = 0 ⇒ x = 4

Substitute each of these values into (1) for corresponding values of y

x = 2 → y = 2 - 5 = - 3 ⇒ (2, - 3 )

x = 4 → y = 4 - 5 = - 1 ⇒ (4, - 1 )

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3 years ago
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