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ElenaW [278]
3 years ago
6

Which ion, when combined with chloride ions, Cl-, forms an insoluble substance in water?

Chemistry
2 answers:
n200080 [17]3 years ago
8 0

Answer is (3) - Pb²⁺.


<em>Explanation;</em>


Among the given choices PbCl₂ is insoluble in water. But it can be soluble in hot water. It appears as white precipitate. The Ksp of PbCl₂ is very small. That's why it is insoluble in water.


Fe²⁺ + 2Cl⁻ → FeCl₂ (soluble in water. Forms pale green color solution)


Mg²⁺ + 2Cl⁻ → MgCl₂ (soluble in water. Forms clear colorless solution)


Pb²⁺ + 2Cl⁻ → PbCl₂ (poorly soluble in water. Forms white precipitation)


Zn²⁺ + 2Cl⁻ → ZnCl₂ (soluble in water. Forms clear colorless solution)



Contact [7]3 years ago
5 0
Pb2 + is the ion, when combined with chloride ions, CI-, forms an insoluble substance in water.
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The common titanium alloy known as T-64 has a composition of 90 weight% titanium 6 wt% aluminum and 4 wt% vanadium. Calculate th
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Explanation:

Suppose in 100 g of alloy contains 90% titanium 6% aluminum and 4% vanadium.

Mass of titanium = 90 g

Moles of titanium = \frac{90 g}{47.87 g/mol}=1.8800 mol

Total number of atoms of titanium ,a_t=1.8800 mol\times N_A

Mass of aluminum = 6 g

Moles of aluminium = \frac{6 g}{26.98 g/mol}=0.2223 mol

Total number of atoms of aluminium,a_a=0.2223 mol\times N_A

Mass of vanadium  = 4 g

Moles of vanadium= \frac{4 g}{50.94 g/mol}=0.0785 mol

Total number of atoms of vanadiuma_v=0.0785 mol\times N_A

Total number of atoms in an alloy = a_t+a_a+a_v

Atomic percentage:

Atomic\%=\frac{\text{total atoms of element}}{\text{Total atoms in alloy}}\times 100

Atomic percentage of titanium:

:\frac{a_t}{a_t+a_a+a_v}\times 100=\frac{1.8800 mol\times N_A}{1.8800 mol\times N_A+0.2223 mol\times N_A+0.0785 mol\times N_A}\times 100=86.20\%

Atomic percentage of Aluminium:

:\frac{a_a}{a_t+a_a+a_v}\times 100=\frac{0.2223 mol\times N_A}{1.8800 mol\times N_A+0.2223 mol\times N_A+0.0785 mol\times N_A}\times 100=10.19\%

Atomic percentage of vanadium

:\frac{a_v}{a_t+a_a+a_v}\times 100=\frac{0.0785 mol\times N_A}{1.8800 mol\times N_A+0.2223 mol\times N_A+0.0785 mol\times N_A}\times 100=3.59\%

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4 years ago
Brass is an alloy of copper and zinc. varying the mass per- centages of the two metals produces brasses with different proper- t
EastWind [94]

First step: The mass of zinc in the yellow zinc sample can be calculated with the help of percentage (given) in the sample. After that, mass of copper is determine by the subtracting the mass of zinc from the total mass of zinc in the given sample.

Thus,

Mass of zinc in 34% zinc sample = 185 g yellow zinc \times \frac{34 zinc}{100 yellow zinc}

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Mass of zinc in 37% zinc sample = 185 g yellow zinc \times \frac{37 zinc}{100 yellow zinc}

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Now,

mass of copper in 34% zinc sample =185 g -62.9 g

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mass of copper in 37% zinc sample = 185 g -68.45 g

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Second step:

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37% zinc sample consist of 63% copper (100-37=63%)

Mass of zinc = (46.5 g copper) \times \frac{34 percent zinc}{66 percent copper}

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Mass of zinc  =46.5 g copper \times \frac{37 percent zinc}{63 percent copper}

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