Answer:
86.5%
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
2Na + 2HF –> 2NaF + H2
Next, we shall determine the theoretical yield of the hydrogen gas, H2. This is illustrated:
From the balanced equation above,
2 moles of Na reacted to produce 1 mole of H2.
Therefore, 5.75 moles of Na will react to produce = (5.75 x 1)/2 = 2.88 moles of H2.
Therefore, the theoretical yield of Hydrogen gas, H2 is 2.88 moles.
Finally, we shall determine the percentage yield of Hydrogen gas, H2. This can be obtained as follow:
Actual yield of H2 = 2.49 moes
Theoretical yield of H2 = 2.88 moles
Percentage yield of H2 =.?
Percentage yield = Actual yield /Theoretical yield x 100
Percentage yield = 2.49/2.88 x 100
Percentage yield = 86.5%
Therefore, the percentage yield of Hydrogen gas, H2 is 86.5%.
