Suppose the original price to be x.
62%x=296.4
Divide both sides by 62% to get x=478, which is the original price.
Answer:
We fail to reject H0; Hence, we conclude that there is no significant evidence that the mean amount of water per gallon is different from 1.0 gallon
Pvalue = - 2
(0.98626 ; 1.00174)
Since, 1.0 exist within the confidence interval, then we can conclude that mean amount of water per gallon is 1.0 gallon.
Step-by-step explanation:
H0 : μ= 1
H1 : μ < 1
The test statistic :
(xbar - μ) / (s / sqrt(n))
(0.994 - 1) / (0.03/sqrt(100))
-0.006 / 0.003
= - 2
The Pvalue :
Pvalue form Test statistic :
P(Z < - 2) = 0.02275
At α = 0.01
Pvalue > 0.01 ; Hence, we fail to reject H0.
The confidence interval :
Xbar ± Margin of error
Margin of Error = Zcritical * s/sqrt(n)
Zcritical at 99% confidence level = 2.58
Margin of Error = 2.58 * 0.03/sqrt(100) = 0.00774
Confidence interval :
0.994 ± 0.00774
Lower boundary = (0.994 - 0.00774) = 0.98626
Upper boundary = (0.994 + 0.00774) = 1.00174
(0.98626 ; 1.00174)
Answer: 1/67600
Step-by-step explanation:
probability that the code is 43MZ:
Probability = (Total Required outcome / total possible outcomes)
Possible outcomes (digit) = (00,.............. ..., 99)
2.) possible outcomes (alphabet) = (A, B,............... .., Z)
P(43MZ) = P(43) × P(M) × P(Z)
P(43) = 1/100
P(M) = 1/26
P(Z) = 1/26
THEREFORE ;
P(43MZ) = (1/100) × (1/26) × (1/26) = 1/67600
Answer:
87 i think
Step-by-step explanation:
I used a calculator
