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jenyasd209 [6]
3 years ago
15

I need the top 2 pls

Mathematics
1 answer:
Andreas93 [3]3 years ago
5 0

Answer:

Step-by-step explanation:

7:8 is 7/8

9:5

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Answer correctly for brainly (not 4
vaieri [72.5K]

Hello there again. I have your answer: Solve for x by simplifying both sides of the equation, then isolating the variable. x = −8

8 0
3 years ago
Read 2 more answers
Mr. Charles gave both of his sons, Joe and Bill, $5,000. Joe deposited the money in an account that offered simple interest of 1
Maksim231197 [3]

Answer:

Bill by $85

Step-by-step explanation:

Bill :  Compound interest is calculated by multiplying the initial principal amount by one plus the annual interest rate raised to the number of compound periods minus one. The total initial amount of the money given  is then subtracted from the resulting value.

Compounded annually for 6 years at 9 % interest Bill would have $8385.50.

Joe : Simple interest at 11% a year The formula we'll use for this is the simple interest formula.

P is the principal amount, $5000.00.

r is the interest rate, 11% per year, or in decimal form, 11/100=0.11.

t is the time involved, 6year(s) time periods.

So, t is 6year time periods.

To find the simple interest, we multiply 5000 × 11 × 6  = 3300

Usually now, the interest is added onto the principal to figure some new amount after 6 year(s),

or 5000.00 + 3300.00 = 8300.00

As you can see Bill has more by $85.

^Check yourself

5 0
3 years ago
Plzzzz help mee plzzzzz plzzzzz
FromTheMoon [43]

Answer:

1. B

2. Seven Hundred thousand nine hundred and four

Step-by-step explanation:

3 0
3 years ago
Please help me with this question!!!!!
Naddika [18.5K]

Answer:

7/25

Step-by-step explanation:

θ lies in quadrant ii

so 2θ lies in quadrant iv

csc θ=5/3

sin θ=3/5 (sin θ=1/csc θ)

[cos(α+β)=cosαcosβ-sinαsinβ]

cos (2θ)=cos(θ+θ)=cos θ cos θ-sin θ sin θ=cos² θ-sin ²θ=1-sin²θ-sin²θ=1-2sin²θ

=1-2 (3/5)²

=1-2(9/25)

=1-18/25

=(25-18)/25

=7/25

5 0
3 years ago
Which strategy would you choose to expand (x+11)(2x+3) and write an equivalent expression
Vlad1618 [11]

Answer:

Step-by-step explanation:

Given the expression (x+11)(2x+3)

We want to expand it and write equivalent expression

Generally if we want to expand an expression we will take one of the expression in one bracket and multiply with the other bracket and then take the other expression and multiply it with the other

E.g, (a+b) × (c + d)

Then, we take a × (c+d) and also b × (c+d)

We can do it the other way round too and it will give the same results.

So, applying this to the given expression

(x+11)(2x+3)

x(2x+3) + 11(2x+3)

2x² + 3x + 22x + 33

2x² + 25x + 33

Then, the equivalent expression is 2x² + 25x + 33

(x + 11)(2x + 3) = 2x² + 25x + 33

5 0
3 years ago
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