4+6+6+2=18(balls)
Another way 1)4+6=10(balls)-green and blue
2)6+2=8(balls)-green and blue
3)10+8=18(balls)-total probability
Answer: 40, 30
Step-by-step explanation:
Answer:
A) 68.33%
B) (234, 298)
Step-by-step explanation:
We have that the mean is 266 days (m) and the standard deviation is 16 days (sd), so we are asked:
A. P (250 x < 282)
P ((x1 - m) / sd < x < (x2 - m) / sd)
P ((250 - 266) / 16 < x < (282 - 266) / 16)
P (- 1 < z < 1)
P (z < 1) - P (-1 < z)
If we look in the normal distribution table we have to:
P (-1 < z) = 0.1587
P (z < 1) = 0.8413
replacing
0.8413 - 0.1587 = 0.6833
The percentage of pregnancies last between 250 and 282 days is 68.33%
B. We apply the experimental formula of 68-95-99.7
For middle 95% it is:
(m - 2 * sd, m + 2 * sd)
Thus,
m - 2 * sd <x <m + 2 * sd
we replace
266 - 2 * 16 <x <266 + 2 * 16
234 <x <298
That is, the interval would be (234, 298)
Answer:
Let the present age of the man be x years.
Age of the man 15 years ago =(x−15) years and
Age of the man 15 years later =(x+15) years
According to the given condition, we have
(x+15)=2(x−15)
⇒x+15=2x−30
⇒x−2x=−30−15
⇒−x=−45 or x=45 years
Hence, the present age of the man is 45 years.
Step-by-step explanation:
Hope it helps you..
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