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3 years ago

Solve. Write your answer in interval notation.

Mathematics

1 answer:

lina2011 [118]3 years ago

3 0

Answer: x < 3 or x ≥ 11

(-∞, 3) or [11, ∞)

Step-by-step explanation:

subtract 4 from each side

2x < 6 . or . 3x ≥ 33

x < 3 or x ≥ 11

make sure you have an OPEN DOT at 3 pointing to negative infinity and a CLOSED DOT at 11 pointing to positive infinity.

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2 years ago

1 /3 + 1 /9 / (7/10 * 5 / 4 )

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Hope it helps..

have a great day : )

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2 years ago

Find the coordinates of point P that lies along the directed line segment AB in a 2:3 ratio given A (-2, 1), B (3, 4).

saul85 [17]

Answer:

$P(x,y) = (0,\frac{11}{5})$

Step-by-step explanation:

Given

$A = (-2,1)$

$B = (3,4)$

$m:n = 2:3$

Required

Determine the coordinates of P

The coordinate of a point when divided into ratio is:

$P(x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})$

Where

$(x_1,y_1) = (-2,1)$

$(x_2,y_2) = (3,4)$

$m:n = 2:3$

This gives:

$P(x,y) = (\frac{2 * 3 + 3 * -2}{2 + 3},\frac{2 * 4 + 3 * 1}{2 + 3})$

$P(x,y) = (\frac{6 - 6}{5},\frac{8 + 3}{5})$

$P(x,y) = (\frac{0}{5},\frac{11}{5})$

$P(x,y) = (0,\frac{11}{5})$

5 0

3 years ago

QUESTION<br> Learning Page<br> AABC and APQR are similar. Find the missing side length.

melisa1 [442]

Answer:

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3 years ago