Using derivatives, it is found that:
i) 
ii) 9 m/s.
iii) 
iv) 6 m/s².
v) 1 second.
<h3>What is the role of derivatives in the relation between acceleration, velocity and position?</h3>
- The velocity is the derivative of the position.
- The acceleration is the derivative of the velocity.
In this problem, the position is:

item i:
Velocity is the <u>derivative of the position</u>, hence:

Item ii:

The speed is of 9 m/s.
Item iii:
Derivative of the velocity, hence:

Item iv:

The acceleration is of 6 m/s².
Item v:
t for which a(t) = 0, hence:




Hence 1 second.
You can learn more about derivatives at brainly.com/question/14800626
Answer:
see below
Step-by-step explanation:
3x^2 + 17x +10 =0
(3x+ ) ( x+ ) =0
We need to factor 10 = 2*5 or 1*10
They are positive since we have all positive terms
3*5 = 15+2 = 17
The 5 needs to multiply the 3 so it goes on the outside
(3x+ ) ( x+ 5 ) =0
That leaves the 2 on the inside
(3x+ 2 ) ( x+ 5 ) =0
Using the zero product property
3x+2 =0 x+5=0
3x = -2 x=-5
x = -2/3 x = -5
Answer:
plot it then see if the line is straight or not
| 42 | The absolute value of forty two