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3 years ago

What is 9 7/8 subtracted by 4 and 5/6

Mathematics

1 answer:

lora16 [44]3 years ago

4 0

5/6 times 97/84 is the answer

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What is the range of this function

34kurt

Answer:

all real numbers such as 0<y<40

Step-by-step explanation:

as the tub is draining water, it will never exceed original amount of 40. the lowest amount of water you can have is 0, never below 0

8 0

3 years ago

8h + (-7.9d) - 14 + 5d - 3.4h

Fynjy0 [20]

☁️ Answer ☁️

So I got:

-2.9d + 4.6h - 14

Hope it helps.

Have a nice day hyung/noona!~ ￣▽￣❤️

7 0

3 years ago

A certain change in a process for manufacture of component parts is being considered. Samples are taken using both the existing

Katyanochek1 [597]

Answer:

a) The confidence interval is $0.00\leq\pi_1-\pi_2\leq0.02$ .

Step-by-step explanation:

We have to calculate a confidence interval (CI) of a difference of proportions.

For the existing procedure, the proportion is:

$p_1=75/1500=0.05$

For the new procedure, the proportion is:

$p_2=80/2000=0.04$

To calculate the CI, we need to estimate the standard deviation

$s=\sqrt{\frac{p_1(1-p_1)}{n_1} +\frac{p_2(1-p_2)}{n_2} }\\\\s=\sqrt{\frac{0.05(1-0.05)}{1500} +\frac{0.04(1-0.04)}{2000} }=\sqrt{ 0.000032 + 0.000019 }=\sqrt{ 0.000051 }\\\\s=0.007$

For a 90% CI, the z-value is 1.64.

Then, the CI is:

$(p_1-p_2)-z*\sigma \leq\pi_1-\pi_2\leq(p_1-p_2)+z*\sigma \\\\(0.05-0.04)-1.64*0.007\leq\pi_1-\pi_2\leq(0.05-0.04)+1.64*0.007\\\\0.01-0.01\leq\pi_1-\pi_2\leq0.01+0.01\\\\0.00\leq\pi_1-\pi_2\leq0.02$

6 0

2 years ago

2 1/2 cases of soda to split between 5 families

Charra [1.4K]

Answer:

OK SO A Which polynomial is prime?

7x2 – 35x + 2x – 10

9x3 + 11x2 + 3x – 33

10x3 – 15x2 + 8x – 12

12x4 + 42x2 + 4x2 + 14

Step-by-step explanation:

Which polynomial is prime?

7x2 – 35x + 2x – 10

9x3 + 11x2 + 3x – 33

10x3 – 15x2 + 8x – 12

12x4 + 42x2 + 4x2 + 14

5 0

2 years ago

ILL GIVE BRAINLIEST!!

densk [106]

Answer:

P(3 , 0)

Step-by-step explanation:

(x₁, y₁) = A(-3,-3) ;(x₂ , y₂) B(5, 1)

m : n = 3 : 1

$P \left( \dfrac{mx_{2}+nx_1}{m+n},\dfrac{my_{2}+ny_{1}}{m+n} \right)\\\\P \left (\dfrac{5*3+(-3)*1}{3+1},\dfrac{3*1+1*(-3)}{3+1} \right)\\\\\\=P \left(\dfrac{15-3}{4},\dfrac{3-3}{4} \right)\\\\\\= P \left(\dfrac{12}{4},\dfrac{0}{4} \right)\\\\\\= P\left(3 , 0 \right)$

5 0

2 years ago