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3 years ago

6

Karl is making a pot of chili. The recipe calls for StartFraction 3 Over 8 EndFraction cup of chili powder, but Karl only wants

to use half as much so it won’t be so spicy. How much chili powder should Karl use?

1 answer:

muminat3 years ago

3 0

Answer:

3/16 or 3 over 16

Step-by-step explanation:

Find half of 3/8:

1/2x3/8 = 3/16

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How to solve 1/4 - -4/3 - -1 2/9

Ahat [919]

Answer:

2 29/36

Step-by-step explanation:

So circle the two signs., so the problem is now this:

1/4+4/3+1 2/9

Then you find the GCM, or Greatest Common Denominator.

It is 36. Then, you re-write the new answers

9/36+ 48/36+ 1 18/36

Now we have this:

1 65/36

The answer is 2 29/36

8 0

3 years ago

Mrs. Leonard is planting a flower garden. She has 18 marigolds for every 6 petunias.

tangare [24]

Answer:

B) 1:3

Step-by-step explanation:

Let's layout the information given firstly.

Marigolds= 18

Petunias= 6

In ratios, you need to follow the arrangement, for say in this question they say petunias go first, so the ratio should involve the value 6 first.

Therefore, it will give you, 6:18.

Now, you need to simplify this ratio. Just simplify it as it were, a fraction. Divide each number by a common factor, in this case, it is 6. Once you've done that, you'll get 1:3.

Hope this helped.

8 0

2 years ago

Read 2 more answers

A selective university advertises that 96% of its bachelor’s degree graduates have, on graduation day, a professional job offer

OLEGan [10]

Answer:

The probability is $P( p < 0.9207) = 0.0012556$

Step-by-step explanation:

From the question we are told

The population proportion is $p = 0.96$

The sample size is $n = 227$

The number of graduate who had job is k = 209

Generally given that the sample size is large enough (i.e n > 30) then the mean of this sampling distribution is

$\mu_x = p = 0.96$

Generally the standard deviation of this sampling distribution is

$\sigma = \sqrt{\frac{p (1 - p )}{n} }$

=> $\sigma = \sqrt{\frac{0.96 (1 - 0.96 )}{227} }$

=> $\sigma = 0.0130$

Generally the sample proportion is mathematically represented as

$\^ p = \frac{k}{n}$

=> $\^ p = \frac{209}{227}$

=> $\^ p = 0.9207$

Generally probability of obtaining a sample proportion as low as or lower than this, if the university’s claim is true, is mathematically represented as

$P( p < 0.9207) = P( \frac{\^ p - p }{\sigma } < \frac{0.9207 - 0.96}{0.0130 } )$

$\frac{\^ p - p}{\sigma } = Z (The \ standardized \ value\ of \ \^ p )$

$P( p < 0.9207) = P(Z< -3.022 )$

From the z table the area under the normal curve to the left corresponding to -3.022 is

$P(Z< -3.022 ) = 0.0012556$

=> $P( p < 0.9207) = 0.0012556$

6 0

3 years ago

I'm a kid i asked that question people do you unerstand

Olegator [25]

YESI had to reread it a couple of times.

5 0

3 years ago

If possible please answer

mrs_skeptik [129]

Answer:

<h2>-3<x≤1 -or- (-3,1]</h2>

4 0

3 years ago