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swat32
4 years ago
15

HURRY PLEASE

Mathematics
1 answer:
klasskru [66]4 years ago
4 0

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

y=0,\:x=6

Step-by-step explanation:

Considering the system of the equations

\begin{bmatrix}2x-7y=12\\ -x+15y=-6\end{bmatrix}

\mathrm{Isolate}\:x\:\mathrm{for}\:2x-7y=12

2x-7y+7y=12+7y

2x=12+7y

Divide both sides by 2

\frac{2x}{2}=\frac{12}{2}+\frac{7y}{2}

x=\frac{12+7y}{2}

\mathrm{Subsititute\:}x=\frac{12+7y}{2}

\begin{bmatrix}-\frac{12+7y}{2}+15y=-6\end{bmatrix}

-\frac{12+7y}{2}+15y=-6

\mathrm{Multiply\:both\:sides\:by\:}2

-\frac{12+7y}{2}\cdot \:2+15y\cdot \:2=-6\cdot \:2

-\left(12+7y\right)+30y=-12

-12+23y=-12

-12+23y+12=-12+12

23y=0

\mathrm{Divide\:both\:sides\:by\:}23

\frac{23y}{23}=\frac{0}{23}

y=0

\mathrm{For\:}x=\frac{12+7y}{2}

\mathrm{Subsititute\:}y=0

x=\frac{12+7\cdot \:0}{2}

x=\frac{12}{2}

x=6

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

y=0,\:x=6

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