Option C:
x = 6 units
Solution:
QR = 7 units, RS = 5 units, UT = 4 units and ST = x
<em>If two secants intersect outside a circle, the product of the secant segment and its external segment s equal to the product of the other secant segment and its external segment.</em>
⇒ SR × SQ = ST × SU
⇒ 5 × (5 + 7) = x × (x + 4)
⇒ 5 × 12 = x² + 4x
⇒ 60 = x² + 4x
Subtract 60 from both sides.
⇒ 0 = x² + 4x - 60
Switch the sides.
⇒ x² + 4x - 60 = 0
Factor this expression, we get
(x - 6)(x + 10) = 0
x - 6 = 0, x + 10 = 0
x = 6, x = -10
Length cannot be in negative measures.
x = 6 units
Option C is the correct answer.
Answer:
<u>84 students </u>
Step-by-step explanation:
See the attached table
As shown there are 20 students from Math club, 7 of them would like to choose calculators.
so, the probability of students who choose calculators = 7/20
If there are 240 students in the Math club
So, the number of students expected to choose calculators = 240 * 7/20
<u>So, the number of students = 84 students </u>
Answer:
Step-by-step explanation:
7x-11=4x+4(being vertically opposite angles)
7x-4x=4+11
3x=15
x=15/3
x=5
angle 2+angle1=180 degree(being straight line)
7x-11+angle 1=180
7*5-11+angle 1=180
35-11+angle1=180
24+angle 1=180
angle 1=180-24
angle 1=156 degree
Sqrt(x^2) = sqrt(20)
x = +2sqrt(5)
x = -2sqrt(5)
x1 = (- 0 + sqrt(0^2 - 4*1*(-20))) / (2*1)
X2 = (-0 - sqrt(0^2 - 4*1*(-20))) / (2*1)
We are given to check
whether these numbers are proportional
we know that any set of numbers are proportional when their ratios are equal
so, firstly we will ratios
First set of numbers:
We are given first set of numbers as 15 , 20 and 30
so, it's ratio is

now, we can simplify it

Since, common factor is 5
so, we can cancel 5
and we get

Second set of numbers:
We are given first set of numbers as 24 , 32 and 48
so, it's ratio is

now, we can simplify it

Since, common factor is 8
so, we can cancel 8
and we get

We can see that both sets of numbers are having same ratios
so, they are proportional.........Answer