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3 years ago

in a bag the coins of 50 Paisa 25 paisa and 10 paisa are in the ratio of 2:3: 5 and its total value is rupees 90

Mathematics

1 answer:

IgorLugansk [536]3 years ago

5 0

Answer:

It is given 50 paise, 25 paise and 10 paise are in the ratio 2:3:5. =4:3:2.

Step-by-step explanation:

Hope this helps

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What is the percent change from 1800 to 1926

Crank

The percentage change is 6.54%
You have to divide 1800÷1926, then multiply by 100 and you'd get 93.46, then subtract 100-93.46 which equals 6.54% :)

4 0

3 years ago

Which expression is equivalent to (4g3h2k4)3

RSB [31]

Answer:

d) $8g^{6}h^{4} k^{12} - (h^{25} k^{15} )$

$\frac{(4g^{3} h^{2}k^{4} )^{3} }{8g^{3}h^{2} } - (h^{5} k^{3} )^{5}$ $= 8g^{6}h^{4} k^{12} - (h^{25} k^{15} )$

Step-by-step explanation:

<u><em>Explanation</em></u>

Given expression

= $\frac{(4g^{3} h^{2}k^{4} )^{3} }{8g^{3}h^{2} } - (h^{5} k^{3} )^{5}$

By using

(ab)ⁿ = aⁿbⁿ

$\frac{a^{m} }{a^{n} } = a^{m-n}$

= $\frac{(4)^{3} g^{9} h^{6}k^{12} ) }{8g^{3}h^{2} } - (h^{5} k^{3} )^{5}$

After simplification , we get

$= 8g^{9}g^{-3} h^{6} h^{-2} k^{12} - (h^{5} k^{3} )^{5}$

$= 8g^{9-3}h^{6-2} k^{12} - (h^{5} k^{3} )^{5}$

$= 8g^{6}h^{4} k^{12} - (h^{25} k^{15} )$

3 0

2 years ago

There is 4/6 of a pizza left from dinner . Each person gets 1/6 of a pizza for lunch the next day . How many people eat the pizz

kolezko [41]

Answer:

4 people eat the pizza for lunch

3 0

1 year ago

The diameter of Joe's large pizza is 19 inches. Approximately how many inches are there in the circumference of the large pizza?

Burka [1]

Answer:

There are 59.66 inches in the circumference of the large pizza.

Step-by-step explanation:

It is given that:

Diameter of Joe's large pizza = 19 inches

Diameter = 2r

2r = 19

Circumference of large pizza = 2πr = 2r * π

Circumference of large pizza = 19*3.14

Circumference = 59.66 inches

Therefore,

There are 59.66 inches in the circumference of the large pizza.

6 0

2 years ago

Which expression is equivalent to (x Superscript 27 Baseline y) Superscript one-third?.

marin [14]

To solve the problem we must know the basic exponential properties.

<h3>What are the basic exponent properties?</h3>

${a^m} \cdot {a^n} = a^{(m+n)}$

$\dfrac{a^m}{a^n} = a^{(m-n)}$

$\sqrt[m]{a^n} = a^{\frac{n}{m}}$

$(a^m)^n = a^{m\times n}$

$(m\times n)^a = m^a\times n^a$

The expression can be written as $x^9\sqrt[3]{y}$ .

Given to us

$(x^{27}y)^\frac{1}{3}$

$(x^{27}y)^\frac{1}{3}$

Using the exponential property $(m\times n)^a = m^a\times n^a$ ,

$=(x^{27}y)^\frac{1}{3}\\\\=x^{\frac{27}{3}}\times y^\frac{1}{3}\\\\=x^9\times y^\frac{1}{3}$

Using the exponential property $\sqrt[m]{a^n} = a^{\frac{n}{m}}$ ,

$=x^9\times y^\frac{1}{3}\\\\=x^9\times \sqrt[3]{y}\\\\=x^9 \sqrt[3]{y}$

Hence, the expression can be written as $x^9\sqrt[3]{y}$ .

Learn more about Exponent properties:

brainly.com/question/1807508

5 0

1 year ago

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in a bag the coins of 50 Paisa 25 paisa and 10 paisa are in the ratio of 2:3: 5 and its total value is rupees 90​

in a bag the coins of 50 Paisa 25 paisa and 10 paisa are in the ratio of 2:3: 5 and its total value is rupees 90