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irina [24]
3 years ago
9

Need help please show how you did it.

Mathematics
1 answer:
jolli1 [7]3 years ago
5 0

Answer:

(0, 1).

Method 1 (Substitution):

Substituting our two y's, we get the following:

x^2 + 5x + 1 = x^2 + 2x + 1 \Rightarrow 3x = 0 \Rightarrow x = 0

Thus, the only set of solutions is (0, 1). A quick sketch (either by hand or on Desmos) can confirm this.

Method 2 (Elimination):

We have two equations. We'll let the top one be equation 1 and the bottom one be equation 2. Eliminating as many variables as we can, we subtract (2) from (1) to get:

0 = 3x => x = 0.

So the only set of solutions is (0, 1).

Method 3 (Gaussian elimination):

We can place this in an augmented matrix and row reduce.

\left[\begin{array}{cccc}1&5&1 & 1\\1&2&1 & 1\end{array}\right]

Row reducing this gives us:

\left[\begin{array}{cccc}1&5&1 & 1\\0&3&0 & 0\end{array}\right]

This tells us that the only solution for x is x = 0 (since we read this as "3x = 0") and thus, the only solution we get is (0, 1).

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Answer:

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Hope this helps! :)

6 0
3 years ago
In considering career options, Ella would like to enter an industry with at least 50% growth from 2000 to 2010. Based on the abo
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Answer:

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Step-by-step explanation:

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All the industries on y axis have the span over x axis representing the growth and salaries.

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8 0
3 years ago
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Derivatives of inverse trigonometric functions please explain answers
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y = cos-1(x2)

This can be described as ' a function of a function'   x^2 is a function of x and cos-1(x^2) is a function of x^2.

We need to  apply the chain rule.

Personally I find this  easier to understand if i let u = x^2, so

If y = f(u) and u is a function of x then

dy/dx = dy/ du * du/dx

Here u = x^2  and y = cos-1(u)

du/dx = 2x

so dy/dx = d(cos-1(x^2) dx = dy/du * du/dx


= -1 / √(1 - u^2) * 2x

= -2x / √(1 - u^2)    

= -2x / √(1 - (x^2)^2)

= -2x / √(1 - x^4)

I hope this helps. but if not. you might like to employ the formulae in the question - The square boxes contain the 'u' s in my answer. These formulae are equivalent to my explanation.

6 0
3 years ago
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