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cestrela7 [59]
3 years ago
11

Which proportion could be used to solve

Mathematics
1 answer:
Brums [2.3K]3 years ago
6 0

Answer:

Cups of carrot needed for 9 servings = 4.5 cups

Step-by-step explanation:

A recipe for sesame chicken calls for cup of chopped carrots

recipe 2 is for 4 servings

That is

2 cups of carrot = 4 servings

2 : 4

= 1 : 2

1 cup of carrot = 2 servings

how many cups of

carrots are needed for 9 servings?

Let x= number of carrot needed for 9 servings

1 : 2 = x : 9

1 /2 = x/ 9

Cross product

1*9 = 2*x

9=2x

Divide both sides by 2

9/2 = x

x= 4.5 Or 4 1/2

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In ΔNOP, n = 170 inches, o = 150 inches and p=290 inches. Find the measure of ∠P to the nearest 10th of a degree.
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Answer:

129.9

Step-by-step explanation:

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4 0
3 years ago
Solve the system of equations.<br><br><br> −5x+2y=9<br> y=7x<br> ​
RUDIKE [14]

Answer:

x=1  y=7

Step-by-step explanation:

−5x+2y=9

y=7x

Substitute the second equation into the first

-5x +2(7x) = 9

Distribute

-5x +14x = 9

Combine like terms

9x=9

Divide by 9

9x/9 =9/9

x= 1

Now find y

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5 0
3 years ago
Read 2 more answers
8. The total weight of a vase and its packaging is: 4 lb. 7 oz. The vase by itself
scoray [572]

Answer:

E

Step-by-step explanation:

the weight of the packaging materials is 12 oz. There are 16 oz in a pound. If the vase weighs 3 lb 11 oz, it would take 5 more oz to reach the next pound, and there was another 7 oz after that. You would then do 5 + 7, which is 12, so the packaging materials weigh 12 oz.

7 0
3 years ago
A survey collected data on annual credit card charges in seven different categories of expenditures: transportation, groceries,
Andru [333]

Answer:

A. Null and alternative hypothesis:

H_0: \mu_d=0\\\\H_a:\mu_d\neq 0

B. Yes. At a significance level of 0.05, there is enough evidence to support the claim that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

P-value = 0.00002

C. As the difference is calculated as (population 1 − population 2), being population 1: groceries and population 2: dinning out, and knowing there is evidence that the true mean difference is positive, we can say that the groceries annual credit card charge is higher than dinning out annual credit card charge.

The point estimate is the sample mean difference d=$840.

The 95% confidence interval for the mean difference between the population means is (490, 1190).

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

Then, the null and alternative hypothesis are:

H_0: \mu_d=0\\\\H_a:\mu_d\neq 0

The significance level is 0.05.

The sample has a size n=42.

The sample mean is M=840.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=1123.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{1123}{\sqrt{42}}=173.2827

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{840-0}{173.2827}=\dfrac{840}{173.2827}=4.848

The degrees of freedom for this sample size are:

df=n-1=42-1=41

This test is a two-tailed test, with 41 degrees of freedom and t=4.848, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=2\cdot P(t>4.848)=0.00002

As the P-value (0.00002) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

At a significance level of 0.05, there is enough evidence to support the claim that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

We have to calculate a 95% confidence interval for the mean difference.

The t-value for a 95% confidence interval and 41 degrees of freedom is t=2.02.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.02 \cdot 173.283=350

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 840-350=490\\\\UL=M+t \cdot s_M = 840+350=1190

The 95% confidence interval for the mean difference is (490, 1190).

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The Sharks have played 5 basketball games this seasons. Their scores are 65,63,67,60, and 65. If they only score 30 points in th
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<span>The list of scores will be: 30 60 63 65 65 67. To get the median, you have to arrange the scores from lowest to highest. The middle number is the median. In this, case there are two numbers in the middle so you have to add the two and then divide by two.</span> <span>Therefore, 63 + 65 = 128 / 2 = 64.</span>
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