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Angelina_Jolie [31]
4 years ago
6

Please answer in a step by step explanation

Mathematics
1 answer:
Sphinxa [80]4 years ago
3 0

Answer:

The answer is A

Step-by-step explanation:

2 less than three-fifths a number means that there is a number multiplied by 3/5 and you subtract two from it. 3/5n-2.

Less than or equal to is the one where the mouth is facing the right and there is a line under it

And then you have 41.

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Square root of 2 divided by the cube root of 2
kifflom [539]

Answer: \sqrt[6]{2}

Step-by-step explanation:

You know that the expression is \frac{\sqrt{2}}{\sqrt[3]{2}}

By definition we know that:

\sqrt[n]{a}=a^{\frac{1}{n}

You also need to remember the Quotient of powers property:

\frac{a^n}{a^m}=a^{(n-m)}

Therefore, you can rewrite the expression:

=\frac{2^{\frac{1}{2}}}{2^{\frac{1}{3}}}

Finally, you have to simplify the expression. Therefore, you get:

=2^{(\frac{1}{2}-\frac{1}{3})}\\=2^{\frac{1}{6}}\\=\sqrt[6]{2}

5 0
3 years ago
Read 2 more answers
She bought a ham, 3 pounds of cheese and an 8-pack of tissues for $17.44. What was the unit price for the tissues?
Sever21 [200]

Answer -9                                                                                                                      

Step-by-step explanation:

-6 divided by 2/3 = -9 2/3 multiplied by -9= -6

7 0
3 years ago
The green triangle is a dilation of the red triangle with a scale factor of s=13 and the center of dilation is at the point (4,2
Arada [10]

Given:

Scale factor s=\dfrac{1}{3}

Center of dilation = (4,2)

To find:

The coordinates of the points C' and A.

Solution:

We know that, if a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

(x,y)\to (k(x-a)+a,k(y-b)+b)

The scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

Suppose the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using rule (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

C(-2,11)\to C'(-2+4,3+2)

C(-2,11)\to C'(2,5)

Hence, the coordinates of Point C' are C'(2,5).

Let us assume that point A is A(m,n).

Using rule (i), we get

A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)

From the given figure it is clear that the image of point A is (8,4).

A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

On comparing both sides, we get

\dfrac{1}{3}(m-4)+4=8

\dfrac{1}{3}(m-4)=8-4

(m-4)=3(4)

m=12+4

m=16

And,

\dfrac{1}{3}(n-2)+2=4

\dfrac{1}{3}(n-2)=4-2

(n-2)=3(2)

n=6+2

n=8

Therefore, the coordinates of point A are (16,8).

4 0
3 years ago
Can you simplify before multiplying 14 x 25/27? Respond with /yes or no/. 10 points!!
ELEN [110]

Answer:

no

Step-by-step explanation:

because 25 cannot go in 27

3 0
4 years ago
Read 2 more answers
Let S = {A, B, C, D} be some set of four elements of a vector space. Suppose that D = 2A + B + 3C and C = A − B. Is {A, B, D} li
Olin [163]

Answer:

As explained

Step-by-step explanation:

given that D = 2A + B + 3C and S = {A, B, C, D}, C = A − B

for {A, B, D}  to be linearly dependent implies that A B and D will have values that not dependent on the sample space C.

if C = A -B is substituted in the original equation, the generated equation, 5A -2B will have values each as against C which is linearly independent.

Also, D will have values that are linearly dependent.

4 0
3 years ago
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