m =(y2-y1)/(x2-x1)
m =(-2 + 3 )/(-3 -2)
m = 1/-5
m = -1/5
slope of the line that is perpendicular = 5
Answer:
z=20
Step-by-step explanation:
(2z + 16) +124 =180
2z + 16 +124
2z + 140 = 180
2z -140 -140
2z = 40
z = 20
Given a polynomial
and a point
, we have that

We know that our cubic function is zero at -4, 0 and 5, which means that our polynomial is a multiple of

Since this is already a cubic polynomial (it's the product of 3 polynomials with degree one), we can only adjust a multiplicative factor: our function must be

To fix the correct value for a, we impose
:

And so we must impose

So, the function we're looking for is

Answer:
JML=142 degrees
Step-by-step explanation:
This shape is a rhombus, as all 4 sides are equal, but the angle measures are not. One of the properties of a rhombus is that opposite angles are congruent, and adjacent angles are supplementary. Only the second one is important. Since angles KLM and angle JML are supplementary, the equation KLM+JML=180 can be used. KLM is then substituted by the given angle measure, 38 degrees, to get an equation such as JML+38=180. Now, to solve for JML, 38 must be subtracted from both sides of the equation, which leaves teh answer of JML=142.