Answer: (a) e ^ -3x (b)e^-3x
Step-by-step explanation:
I suggest the equation is:
d/dx[integral (e^-3t) dt
First we integrate e^-3tdt
Integral(e ^ -3t dt) as shown in attachment and then we differentiate the result as shown in the attachment.
(b) to differentiate the integral let x = t, and substitute into the expression.
Therefore dx = dt
Hence, d/dx[integral (e ^-3x dx)] = e^-3x
Answer:
Symbol
Step-by-step explanation:
the object <em>symbolizes</em> something else
The amount borrowed from the the lender that charges 4.4% interest is $1000.
The amount borrowed from the the lender that charges 5.7% interest is $1500.
<h3>What are the linear equations that can be derived from the question?</h3>
a + b = $2500 equation 1
0.088a + 0.114b = $246 equation 2
Where:
a = amount borrowed from the lender that charges 4.4% interest
b = amount borrowed from the lender that charges 5.7% interest
<h3>How much was
borrowed from the
lender that charges 5.7% interest?</h3>
Multiply equation 1 by 0.114
0.114a + 0.114b = 285 equation 3
Subtract equation 2 from equation 3
39 = 0.026b
b = $1500
<h3>How much was
borrowed from the
lender that charges 4.4% interest?</h3>
Substitute for b in equation 1
a + $1500 = $2500
a = $2500 - $1500
a = $1000
To learn more about simultaneous equations, please check: brainly.com/question/25875552