9514 1404 393
Answer:
47 -6√10
Step-by-step explanation:
As you know, the area of a square is the square of the side length. It can be helpful here to make use of the form for the square of a binomial.
(a -b)² = a² - 2ab + b²
(√2 -3√5)² = (√2)² - 2(√2)(3√5) + (3√5)²
= 2 - 6√10 + 3²(5)
= 47 -6√10
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<em>Check</em>
√2-3√5 ≈ -5.29399 . . . . . . . . note that a negative value for side length makes no sense, so this isn't about geometry, it's about binomials and radicals
(√2-3√5)² ≈ 28.02633
47 -6√10 ≈ 28.02633
Answer: He has planted 2/3 and there is 1/3 left to plant.
Explanation: You need to add your fractions together, because each of those is a section of the garden and you need the total of how much of the garden he has planted.
This isn’t too difficult because the denominators are the same.
5/12 + 3/12 = 8/12
It is 8/12 because since the denominators are the same, you just need to add the numerators. Imagine you have a pie that’s cut into 12 pieces, and you and your friends take 5, and then your family takes 3. How many or gone now? 8 pieces. From how many pieces? 12 pieces. So 8/12 pieces are gone.
So Peter has planted 8/12 of his garden. This however, can be simplified, because both of those numbers divide by 4.
8/4 = 2
12/4 = 3
So 8 is now 2, and 12 is now 3.
This is now 2/3.
If there is 2/3 gone, you need to figure out how much is left to get you to 1.
In this instance, 1 can be rewritten as 3/3, because 3 divided by 3 is 1.
In order to get from 2/3 to 1, you need to add 1/3, one more third to the two thirds you already have.
This means Peter has 1/3 left to plant.
Hope this helps :)
Answer:
x=2 y=7
Step-by-step explanation:
Add the equations in order to solve for the first variable. Plug this value into the other equations in order to solve for the remaining variables.
Answer:
Choice 4.
Step-by-step explanation:
f(g(x))
Replace g(x) with x^2+8 since g(x)=x^2+8.
f(g(x))
f(x^2+8)
Replace old input,x, in f with new input, (x^2+8).
f(g(x))
f(x^2+8)
2(x^2+8)+5
Distribute:
f(g(x))
f(x^2+8)
2(x^2+8)+5
2x^2+16+5
Combine like terms:
f(g(x))
f(x^2+8)
2(x^2+8)+5
2x^2+16+5
2x^2+21
