You want to draw 2 kings from a 52 card deck. And you do it with replacement.
There are 4 kings in a standard deck. The probability of getting one of them is
4/52 on the first draw.
For the second draw the probability is the same.
4/52
The probability for both happening is
(4/52)*(4/52) = (1/13)*(1/13) = 1/169 = 0.001597
Answer:
T=4
Step-by-step explanation:
it is just half of what the other side is if one side is like 1 1/2 then you just break the other side in half and that will give you T.
Difference of two squares will be
16y^2 -x^2 = (4y -x)(4y +x)
so the second choice
100% - x
115% - 84.87
x=(100*84.87)/115=73.8
Answer:
See proof below
Step-by-step explanation:
Assume that V is a vector space over the field F (take F=R,C if you prefer).
Let 
. Then, we can write x as a linear combination of elements of s1, that is, there exist 
and 
such that 
. Now, 
then for all 
we have that 
. In particular, taking 
with 
we have that 
. Then, x is a linear combination of vectors in S2, therefore 
. We conclude that 
.
If, additionally 
then reversing the roles of S1 and S2 in the previous proof, 
. Then 
, therefore 
.
