Simplify or compute: a·a·a/3a

Mathematics

1 answer:

olga55 [171]3 years ago

8 0

Answer:

. I I wish I could help. <em>Sorry</em>

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a dog searching for a bone walks 3.5 m southeast, then 8.2 m at an angle 30 degrees north of east. Find the magnitude of the dog

lianna [129]

Answer:

Step 1: Firstly, we draw both of the axes.

Step 2: We then draw a vector of length 3.5 m (theoretical) along the (-x) axis.

Step 3: Next, we draw a vector of length 8.2 m from the endpoint towards to top, at an angle of 60° from that point (N.B: 90-30, since it is required to make a 30°∠ with the current vertical; eventually the triangle being formed will be 90° minus the 30°.) Most importantly, the 8.2 m vector should be drawn in such a way so that it is higher than the starting point of the 3.5 m vector. )

Step 4: Lastly, we draw a 15 m vector from the endpoint of the 8.2 m vector, running above the original vector, and to the left. This one should be drawn on the left side, and must be situated far enough.

∴ Triangle 1 () is of angles 30°, 60° and 90°;

On solving for the vertical side (the slope similar to the 3.5 vector), we get

(8.2/2) m = 4.1 m

Next, we solve for the opposite side via 4.1 × √3= 7.1 m

Moving on to Triangle 2 (),

top side = (15 - 7.1) m = 7.9 m

similarly, right side = (4.1 - 3.5) m = 0.6 m

∴ last side = resultant displacement:

⇒ + (0.6)² = 7.9 m

and, direction of displacement = arcTan(y/x)

= arcTan(0.6/7.9)

= 4.3° north of west

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4 years ago

What gives a whole number multiplying, 0.65 and 58 by 10 or 100

HACTEHA [7]

The correct answer is 10! Just asked Siri!

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3 years ago

Read 2 more answers

Triangle A E C is shown. Line segment B D is drawn near point C to form triangle B D C.

AVprozaik [17]

∠BDC and ∠AED are right angles, is a piece of additional information is appropriate to prove △ CEA ~ △ CDB

Triangle AEC is shown. Line segment B, D is drawn near point C to form triangle BDC.

<h3> What are Similar triangles?</h3>

Similar triangles, are those triangles which have similar properties,i.e. angles and proportionality of sides.

Image is attached below,
as shown in figure
∡ACE = ∡BCD ( common angle )
∡AED = ∡BDC ( since AE and BD are perpendicular to same line EC and make right angles as E and C)
∡EAC =- ∡DBC ( corresponding angles because AE and BD are parallel lines)

Thus, △CEA ~ △CDB , because of the two perpendiculars AE and BD.

Learn more about similar triangles here:
brainly.com/question/25882965

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