Part A:

Given that Nicholas's school is located at point (3, 2) and that the post office is located at point (-2, -2), then the distance between Nicholas's school and the post office is given by:

$d= \sqrt{(-2-3)^2+(-2-2)^2} \\ \\ = \sqrt{(-5)^2+(-4)^2} = \sqrt{25+16} \\ \\ \sqrt{41} =\bold{6.4} \ units$

Part B:

If Nicholas is located at point (– 3 , 2), the distance to get to the grocery store located at point (1,-1) is given by:

$d= \sqrt{(1-(-3))^2+(-1-2)^2} \\ \\ = \sqrt{(1+3)^2+(-3)^2} = \sqrt{(4)^2+9} \\ \\ = \sqrt{16+9} = \sqrt{25} =\bold{5}$

4 0

3 years ago

2(n+5)=-2 step by step plz

Elodia [21]

Answer:

n=-6

Step-by-step explanation:

2(n+5)=-2

distribute

2(n+5)

2xn 2x5

2n+10

2n+10=-2

subtract 10 from both sides

10-10=0

-2-10=-12

2n=-12

divide each side by 2

2n/2=n

-12/2=-6

n=-6

6 0

3 years ago

Sklyer has 15 less than twice as many customers as when she started selling newspapers. She now has 155 customers. How many did

arlik [135]

155 = 2x -15
170 = 2x
85 = x

She had 85 when she first started.

8 0

3 years ago

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