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Paladinen [302]
3 years ago
7

How do you find one angle to a triangle that you already know two of them?

Mathematics
1 answer:
svp [43]3 years ago
3 0

Answer:

Formula:

a+b+c=180°

If you want to find one them simply make an equation:

a=180-b-c

Example:

a=60° b=30° c=?

c=180-60-30

c=90°

Good luck!

Intelligent Muslim,

From Uzbekistan.

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In a coordinate plane, triangle ABC has vertices A(- 4, 5), B(- 4, - 4) , and C(3,-4), . Find the perimeter of triangle ABC to t
4vir4ik [10]

Answer: perimeter of triangle ABC to the nearest tenth = 27.4

Step-by-step explanation: Given that

vertices are

A(- 4, 5), B(- 4, - 4) , and C(3,-4)

Length AB = root( [-4-5]^2 + [-4+4]^2)

Length AB = sqr(9^2) = 9

Length AC = root( [-4-5]^2 + [3+4]^2)

Length AC = sqr( 9^2 + 7^2)

Length AC = sqr(130) = 11.4

Length BC = root( [-4+4]^2 + [3+4]^2)

Length BC = sqr( 7^2) = 7

Perimeter = 9 + 11.4 + 7 = 27.4

7 0
3 years ago
Does the following represent a function? <br> f = [ (3, -1), (2, 5), (4, -6), (3, 4), (5, -8) ]
ella [17]

Answer:

Not a function

Since x= produces y- -1 and y=-4, the relation (3,-1),(2,5),(4,-6),(3,4),(5,-8) is not a function.

7 0
2 years ago
Differentiate the function with respect to x<br> f(x)= x^4/ x^2- 4<br> Show work
jeyben [28]

Answer:

Step-by-step explanation:

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7 0
2 years ago
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We are given this

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use the formula for the difference of cubes

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Now use the formula for the difference of squares as 4y = (2\sqrt{y} )^2

(x-2\sqrt{y}) (x+2\sqrt{y}) (x^4+4x^2y+16y^2)

7 0
3 years ago
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