Answer:
Step-by-step explanation:
*Missing Part of the Question*
4 stars
5 triangles
3 circles
3 squares
Required
Determine the probability of triangle being first then square being second
Represent the triangle with T and square with S
So, we're solving for P(T n S)
Solving for P(T)
Solving for P(S)
The question implies a probability without replacement;
Hence Total has now been reduced by 1
Total = 14
Recall that
Hence, the required probability is
Answer:
2 is the correct option.
Step-by-step explanation:
We have the equation 
.
We will plot the graphs of the function 
and 
.
Then, the intersection points of both the graph will be the solution of the equation .
From the graphs, we see that,
The intersection points of the graphs are (0,1) and (2.337,10.347).
The solution of the equation is the value of 'x' co-ordinate where they intersect.
So, we get, x = 2 is the correct option.
Answer: 28-6x
This is the same as -6x+28
===============================
To get that answer, you multiply each term inside the parenthesis by the outer term 2
14 * 2 = 28
-3x * 2 = -6x
So,
(14-3x)*2 = 14*2 - 3x*2 = 28-6x
----------
The distribution rule says
a(b-c) = ab-ac
which is the same as saying
(b-c)a = ba-ca
We can flip things around because we can multiply in any order.
The answer is 4,162 for 564+3,598
<span>0.05 arc-second = 1 degree/72000 = (pi
radians)/(180*72000) = 2.424 x 10^(-7) radians</span>
<span>The distance is roughly: </span>
<span>R*(theta) = (600 light-years)*2.424 x 10^(-7) = 0.00014544 light-years = 1.275
light-hours = (3600 seconds)*(3 x 10^8 m/s)*(1.275) = 1.38 x 10^12 meters.</span>
