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3 years ago

What is the equation in point-slope form of a line that passes through the points (5, −3)(5, −3) and (−2, 9)(−2, 9) ?

1 answer:

5 0

Point sloe is
y-y1=m(x-x1)
slope=m
a ponint is (x1,y1)

slope=(y2-y1)/(x2-x1)
(x,y)
(5,-3)
(-2,9)
slope=(9-(-3))/(-2-5)=12/-7=-12/7
m=-12/7

a point is (5,-3)
x1=5
y=-3
y-(-3)=-12/7(x-5)
y+3=-12/7(x-5)

2nd one

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sergiy2304 [10]

Answer:

$4(x^{2} -4)^{2} -76$

Step-by-step explanation:

Take out 4:

4(x^2-8x)-12

=4(x^2-8x+16-16)-12

=4(x^2-8x+16)-64-12

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2 years ago

The legend on a map states that 1

Firdavs [7]

Answer:

$Actual = 480\ miles$

Step-by-step explanation:

Given

$Map : Actual = 1\ in: 80\ miles$

Required

Find actual distance when map distance = 6 inches

Substitute 6 for Map in $Map : Actual = 1\ in: 80\ miles$

$6\ in: Actual = 1\ in: 80\ miles$

Express as fractions

$\frac{6\ in}{Actual} = \frac{1\ in}{80\ miles}$

$\frac{6}{Actual} = \frac{1}{80\ miles}$

Cross Multiply

$Actual * 1 = 6 * 80\ miles$

$Actual = 6 * 80\ miles$

$Actual = 480\ miles$

<em>Hence, the actual distance is 480 miles</em>

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3 years ago

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Mrrafil [7]

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arlik [135]

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Deffense [45]

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