Answer:
A = 6
So
Side A = 6
Side B = 11
Side C = 3
Side D = 13
Explanation:
To solve perimeter of a quadrilateral, you use this formula:
side A + side B + side C + side D = total perimeter.
If the four sides are A, A + 5, A – 3, and 2A + 1 then you need to solve for A.
Write out an algebraic formula with these values:
A + (A + 5) + (A – 3) + (2A + 1) = P
You also know that the total perimeter is 33, so :
A + (A + 5) + (A – 3) + (2A + 1) = 33
You can add all the A values together to combine like terms like this:
5A + 5 – 3 + 1 = 33
Solve fore A:
5A + 3 = 33
5A = 33 – 3
5A = 30
A = 30 ÷ 5
A = 6
Check your answer:
A + (A + 5) + (A – 3) + (2A + 1) = 33
(6) + ((6) + 5) + ((6) – 3) + (2(6) + 1) = 33
(6) + (11) + (3) + (13) = 33
17 + 16 = 33
33 = 33
first off, I'd like to point out that for the 5th test, he has 96, and that's +6 above 90, and therefore it should be 6.
if all the above/below numbers, summed up yield 0, that simply means the average is an even 90 on average for all 6 tests, if they yield above 0, is above on the average, and if it's below 0, a negative value, he needs to do more work.
-7+4-11+7+6-3 = -4.
you can think of it this way, if he had 90 on all 6 tests, the above/below row will show 0, 0, 0, 0, 0, 0. If any of the tests was above 90, that row will yield a sum more than 0, and if any of the tests were below, that sum will be a negative value.
Answer:
(2, 5)
Step-by-step explanation:
Given the 2 equations
y = x + 3 → (1)
- 2x + y = 1 → (2)
Substitute y = x + 3 into (2)
- 2x + x + 3 = 1
- x + 3 = 1 ( subtract 3 from both sides )
- x = - 2 ( multiply both sides by - 1 )
x = 2
Substitute x = 2 into (1) for corresponding value of y
y = 2 + 3 = 5
Solution is (2, 5)
Given the statement, "If
is odd, then
is odd," its contrapositive claims that, "If
is not odd, then
is not odd."
So assume
is not odd, i.e.
is even. This means there is an integer
for which
. Squaring this gives
.
Well, we can write
, and
is just another integer, which means
must be even.
