
<em>combine like terms</em>

Answer:
-2
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
4(3+c)+c=c+4
(4)(3)+(4)(c)+c=c+4(Distribute)
12+4c+c=c+4
(4c+c)+(12)=c+4(Combine Like Terms)
5c+12=c+4
5c+12=c+4
Step 2: Subtract c from both sides.
5c+12−c=c+4−c
4c+12=4
Step 3: Subtract 12 from both sides.
4c+12−12=4−12
4c=−8
Step 4: Divide both sides by 4.
4c
4
=
−8
4
c=−2
Answer:
The 95% confidence interval estimate for the true proportion of adults residents of this city who have cell phones is (0.81, 0.874).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval estimate for the true proportion of adults residents of this city who have cell phones is (0.81, 0.874).
Answer:
Step-by-step explanation:
When Riko left his house, Yuto was 5.25 miles along the path.
Average speed of Riko = 0.35 miles per minute
Average speed of Yuto = 0.25 miles per minute
First we will calculate the time in which Riko will catch Yuto on the track.
Relative velocity of Riko as compared to Yuto will be = velocity of Riko - velocity of Yuto
= 0.35 - 0.25
= 0.10 miles per minute
Now we this relative velocity tells that Riko is moving and Yuto is in static position.
By the formula,
Average speed = 
0.10 = 
t = 
t = 52.5 minutes
Now we know that Rico will catch Yuto in 52.5 minutes. Before this time he will be behind Yuto.
So duration of time in which Rico is behind Yuto will be 0 ≤ t ≤ 52.5
Here time can not be less than zero because time can not be with negative notation. It will always start from 0.
Answer:
Step-by-step explanation:
<u>Total outcomes:</u>
<u>Outcomes with same numbers on both dice:</u>
<u>Outcomes with different numbers on both dice:</u>
<u>Probability of different numbers on both dice:</u>