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IRISSAK [1]
3 years ago
8

X-2<3 I can’t do this I have adhd so it is really hard for me

Mathematics
2 answers:
Vlad [161]3 years ago
5 0

Answer:

how much does it say that x equals?

dlinn [17]3 years ago
5 0
Hi I am not sure what you are looking for with “X-2<3” but if it is looking for the inequality form it is x < 5. Interval notation is -infinity, 5
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List the integers that satisfy both these inequalities, 2x+9 -12
Flura [38]

Answer:

x < -10.5

Step-by-step explanation:

list the integers that satisfy both these inequalities, 2x+9 <-12

Subtract 9 from  both sides;

2x +9 - 9 < -12-9

2x < -21

x < -21/2

x < -10.5

<em>Hence all the integers are values of x less than 10.5</em>

<em></em>

4 0
3 years ago
What are all the common factors?
lord [1]

Answer:

2,3,6

Step-by-step explanation:

8 0
4 years ago
What are the x and y-intercepts of the line described by this equation? -6x+3y=18.9?
Naddika [18.5K]

The "x" intercept is found when you plug in "0" for "y"
  -6x + 3(0) = 18.9
        -6x = 18.9  (Divide both sides by -6)
           x = - 3.15
           (-3.15, 0)  is your x-intercept

Now plug in "0" for the x
-6(0) + 3y = 18.9
          3y = 18.9  (Divide both sides by 3)
                y = 6.3
               (0, 6.3) is your y - intercept






































5 0
4 years ago
rotation of 90 degrees counterclockwise about the origin, point O, then a reflection across the x-axis reflection across the y-a
SpyIntel [72]

Answer:

The point O can be (x,y)  or (-x,y) or (-x,-y) or ( x,-y) reason being that you haven't given point O lies in which quadrant.

Rotation through 90° counter clockwise

(x,y) = (-y,x)

(-x,y)=(-y,-x)

(-x,-y)=(y,-x)

(x,-y) =(y,x)

Then Reflection across X axis has taken place.

(-y,x) = (-y,-x)

(-y,-x)=(-y,x)

(y,-x)=(y,x)

(y,x)=(y,-x)

Then a reflection across the y-axis has taken place.

(-y,-x)=(y,-x)

(-y,x) = (y,x)

(y,x) =(-y,x)

(y,-x)=(-y,-x)

Then a translation a units to the right and b units up has taken place.

(y,-x)=(y+a,-x+b)

(y,x) =(y+a, x+b)

(-y,x) =(-y+a,x+b)

(-y,-x)=(-y+a,-x+b)

Then a rotation of 180 degrees counterclockwise about the origin has taken place.

(y+a,-x+b)=[-(y+a),-(-x+b)]

(y+a, x+b)=[- (y+a), -(x+b)]

(-y+a,x+b)=[-(-y+a),-(x+b)]

(-y+a,-x+b) =[-(-y+a),-(-x+b)]

Now Again a reflection across the Y axis has taken place.

[-(y+a),-(-x+b)]=[(y+a),-(-x+b)]

[-(y+a),-(x+b)]=[(y+a),-(-x+b)]

[-(-y+a),-(x+b)]=[(-y+a),-(x+b)]

[-(-y+a),-(-x+b)]=[(-y+a),-(-x+b)]

Totally depends on value of a and b on which quadrant these point lies.



7 0
3 years ago
What is the value of x3 . y4 when x<br> 3 and y = 0?
jonny [76]

Answer:

<h2>0</h2>

Step-by-step explanation:

x^3 \times y^4\\\\x = 3\\y =0 \\\\(3)^3\times 0^4\\\\3^3\times\:0^4\\\\\mathrm{Apply\:rule}\:0^a=0\\0^4=0\\\\=3^3\times\:0\\\\\mathrm{Apply\:rule}\:0\times\:a=0\\=0

6 0
4 years ago
Read 2 more answers
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