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Lisa [10]
3 years ago
14

Another one: (12 - 7.5) - 7

Mathematics
1 answer:
mixas84 [53]3 years ago
5 0

Answer:

-2.5

Step-by-step explanation:

Plugged into calculator

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Please help me with my hw thank you so much
Yuri [45]

Answer: d

Step-by-step explanation:

8 0
3 years ago
WILL GIVE BRAINLIEST! Find k so that (5, k) is equidistant from (–1, 2) and (3, 0).
pochemuha

Answer:

9

Step-by-step explanation:

So first I created 2 distance forumlas and set them equal to each other

\sqrt{(5+1)^2+(k-2)^2} =\sqrt{(5-3)^2+(k)^2}

then I simplified them

(5+1)^2+(k-2)^2 =(5-3)^2+(k)^2\\

36 + k^2 - 4k +4 = k^2 + 4

-4k + 36 = 0\\

4k = 36

k = 9

when k = 9, the two distances are equal

7 0
4 years ago
Can someone please help me and ill give you brainliest
Anna11 [10]

Answer:

H = 14.33 i think

Check in with me if it is wrong

3 0
3 years ago
Read 2 more answers
What is the circumference
Butoxors [25]
Are you asking for the definition of circumference? because you didn’t attach a picture or give us an equation to do.
5 0
3 years ago
A, b, c and d are positive integers, such that a+b+ ab = 76, c+d+ cd = 54. Find (a+b+c+d)·a·b·c·d.
lutik1710 [3]

Notice that

(1 + <em>x</em>)(1 + <em>y</em>) = 1 + <em>x</em> + <em>y</em> + <em>x y</em>

So we can add 1 to both sides of both equations, and we use the property above to get

<em>a</em> + <em>b</em> + <em>a b</em> = 76  ==>  (1 + <em>a</em>)(1 + <em>b</em>) = 77

and

<em>c</em> + <em>d</em> + <em>c d</em> = 54  ==>  (1 + <em>c</em>)(1 + <em>d</em>) = 55

Now, 77 = 7*11 and 55 = 5*11, so we get

<em>a</em> + 1 = 7  ==>  <em>a</em> = 6

<em>b</em> + 1 = 11  ==>  <em>b</em> = 10

(or the other way around, since the given relations are symmetric)

and

<em>c</em> + 1 = 5  ==>  <em>c</em> = 4

<em>d</em> + 1 = 11  ==>  <em>d</em> = 10

Now substitute these values into the desired quantity:

(<em>a</em> + <em>b</em> + <em>c</em> + <em>d</em>) <em>a</em> <em>b</em> <em>c</em> <em>d</em> = 72,000

6 0
3 years ago
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