The subtraction of complex numbers 
is cos(π)+i sin(π).
Given 
[cos(3π/4+i sin(3π/4) and 
=cos (π/2) +i sin(π/2)
We have to find the value of .
A complex number is a number that includes real number as well as a imaginary unit in which 
. It looks like a+ bi.
We have to first solve 
and then we will be able to find the difference.
[ cos (3π/4)+i sin (3π/4)]
[cos(π-π/4)+ i sin (π-π/4)]
= [-cos(π/4)+sin (π/4)]
=(-1/+1/)
=
=0
cos(π/2)+i sin (π/2)
=0+i*1
=1
Now putting the values of 
,
=-1
=-1+i*0
=cos (π)+i sin(π)
Hence the value of difference between is cos(π)+i sin(π).
Learn more about complex numbers at brainly.com/question/10662770
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The answer to ur question is (D.4)
Answer:
c. $467.29
Step-by-step explanation:
The total of balances is $9360. The payment can be computed using the amortization formula:
A = P(r/12)/(1 -(1 +r/12)^-n)
where A is the monthly payment, P is the principal (total balance), r is the annual rate, and n is the number of months.
Filling in your numbers, we have ...
A = $9360(0.18/12)/(1 -(1 +0.18/12)^-24) ≈ $467.29
Frank's monthly credit card payment will be $467.29.
Answer:
8
Step-by-step explanation:
let the numbers be x,x+1,x+2
x+x+1+x+2=27
3x+3=27
3x=27-3=24
x=24/3=8
