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Ronch [10]
3 years ago
10

Solve for cos(theta) in sin^2(theta) + cos^2(theta) = 1.

Mathematics
1 answer:
miv72 [106K]3 years ago
3 0
Subtract the sine term and take the square root.
cos(\theta)^{2} = 1 - sin(\theta)^{2}
cos(\theta) = \pm \sqrt{1 - sin(\theta)^{2}}
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3(x - 2) + 48 = -3x
kow [346]

Answer: X=-7

Step-by-step explanation:

Using PEMDAS;

Step 1: Distribute the "3" in the part of the equation "3(x-2)"

3x - 6

Step 2: Consider the equation as a whole with the newly part of the equation from step 1, as it is a part of the equation

Therefore, re-written as,

3x - 6 + 48 = -3x

Step 3: Evaluate the re-written equation

Using basic mathematics skills, we can evaluate the following,

3x - 6 + 48 = -3x ➡ -6 + 48 = -6x ➡ 42 = -6x ➡ -7 = x

As shown, the answer is x=-7.

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