ameena is printing the class newsletter there are 8 pages in the newsletter and she needs 74 copies . Each package of paper cont
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Answer:
The Area of the base is 16 cm² .
Step-by-step explanation:
Given as :
The surface area of the cuboid = x = 95 cm²
The lateral surface area of the cuboid = y = 63 cm²
Let The Area of the base = z cm²
Now, Let The length of cuboid = l cm
The breadth of cuboid = b cm
The height of cuboid = h cm
<u>According to question</u>
∵ The surface area of the cuboid = 2 ×(length × breadth + breadth × height + height × length)
Or, x = 2 ×(l × b + b × h + h × l)
Or, 95 = 2 ×(l × b + b × h + h × l)
Or, (l × b + b × h + h × l) = ....1
<u>Similarly</u>
∵lateral surface area of the cuboid = 2 ×(breadth × height + length × height)
Or, y = 2 ×(b × h + l × h)
Or, 2 ×(b × h + l × h) = 63
Or, (b × h + l × h) = ......2
Putting value of eq 2 into eq 1
so, (l × b + ) =
Or, l × b = -
Or, l × b =
i.e l × b =
so, l × b = 16
<u>Now, Again</u>
∵The Area of the base = ( length × breadth ) cm²
So, z = l × b
i.e z = 16 cm²
So, The Area of the base = z = 16 cm²
Hence,The Area of the base is 16 cm² . Answer
Answer:
<em>Option B; False</em>
Step-by-step explanation:
Consider a Triangle Inequality to prove that these segments could form a triangle;
<em>These segments could not form a triangle</em>
Step-by-step explanation:
Cubes have square faces, so the area of the base is b².
The volume of the cube is b³.
The height of each pyramid is half the height of the cube, so h = b/2. Which means b = 2h.
The cube is made of 6 square pyramids with the same base and height. Therefore, each pyramid has 1/6 the volume of the cube. So the volume of each pyramid is b³/6.
Answer:
C
Step-by-step explanation:
Since the triangle is right with hypotenuse QR
Use Pythagoras' identity to solve for QR
The square on the hypotenuse is equal to the sum of the squares on the other two sides, that is
QR² = 8² + (8 )²
= 64 + 192
= 256 ( take the square root of both sides )
QR = = 16