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TEA [102]
3 years ago
5

What are four kinds of parabolas

Mathematics
1 answer:
patriot [66]3 years ago
3 0
Solutions 

<span>A right handed parabola: </span>y^2=4ax<span><span>

</span></span>A left handed parabola: y^2=-4ax<span>

</span>An up facing parabola: x^2=4ay<span>

</span>A down facing parabola: x^2=-4ay
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What is the unit rate for the Japanese bullet train?
alisha [4.7K]

Answer:

186 Miles per hour.

Step-by-step explanation:

558/3

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2 years ago
a)express x^2+12x+11 in the form (x+p)^2+q b)A curve has equation y=x^2+12x+11. What are the co-ordinates of the turning point o
sveticcg [70]

a) (x+6)^2-25

b) (-6, -25)

Step-by-step explanation:

Perfect square trinomial! If you have 12x, divide by two and get 6, so we have (x+6)^2+q. Then solve for q. You get q as -25.

For b, we just take the vertex from vertex form. We get x+6=0 so x=-6, and q = -25, so the answer is (-6, -25).

Hope that helped,

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4 0
3 years ago
Will mark brainliest !!
ikadub [295]

Given Fig.is a triangle

Perimeter is simply sum of the all sides of a triangle

1/3x + 7/x^2 + (x+2)/x

=[ x+ 21 + 3x(x+2)]/3x^2

= (x+ 21 + 3x^2 + 6x)/3x^2

= (3x^2 + 7x +21)/3x^2

7 0
3 years ago
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Evaluate rq2 + 3qr + r2 for r = 5 and q = 2
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Jeff was already 7 miles out of town when his sister
Nikolay [14]

The sister catches up Jeff after 2 hours

Step-by-step explanation:

We can write Jeff's position and his sister position at time t using the following expressions:

- Jeff position:

x_j(t) = 7 + 2.5 t

where:

7 is the initial position of Jeff when his sister sarts chasing him

2.5 is Jeff's velocity (in miles/hour), so its position increases by 2.5 miles for each hour

t is the time measured in hours

- Sister position:

x_s(t) = 6t

where

6 is the sister velocity (her position increases by 6 miles for every hour)

t is the time measured in hours

The sister catches up Jeff when the two positions are equal, so

x_j(t) = x_s(t)\\7+2.5t=6t

And solving for t,

7+2.5t-2.5t=6t-2.5t\\7=3.5t\\t=\frac{7}{3.5}=2 h

So, the sister catches Jeff after 2 hours.

Learn more about speed:

brainly.com/question/8893949

#LearnwithBrainly

5 0
3 years ago
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