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Travka [436]
3 years ago
15

The probability that Terri will draw a heart and then a red face card from a standard 52-card deck is . Using this probability,

determine if the event of drawing a heart and the event of drawing a red face card was independent, dependent, both, or neither.
Mathematics
1 answer:
Anestetic [448]3 years ago
7 0
<h3>The both events are <u>not independent</u> as the intersection of outcomes of both the events is 3  and  not equal to Ф.</h3>

Step-by-step explanation:

Here, the total number of cards in a deck = 52

The total number of heart cards  =  13

The total number of red faces in the deck  = 6 ( 3 of heart and 3 of diamonds)

Now, out of the TOTAL 6 red face cards, 3 are of hearts.

So, (Red cards) ∩ (Heart cards)  = 3 cards ( J, Q and K)

Now let E : Event of picking card which is of heart.

P(E) = \frac{\textrm{Total number of red hearts}}{\textrm{Total cards}}  = \frac{13}{52}  = (\frac{1}{4})

So, the probability of picking a heart = \frac{1}{4}

Now let F : Event of picking card which is of red face.

P(E) = \frac{\textrm{Total number of red faces}}{\textrm{Total cards}}  = \frac{6}{52}  = (\frac{3}{26})

So, the probability of picking a red face card  = \frac{3}{26}

Hence, the both events E and F are <u>not independent</u> as the intersection of outcomes of both the events is 3  and  not equal to \phi.

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Aloiza [94]

Answer:

11.4 feet

Step-by-step explanation:

Using the right triangle formed by the tent pole, the ground and the guy rope,  where the guy rope (g) is the hypotenuse.

Applying Pythagoras' identity

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

g² = 9² + 7² = 81 + 49 = 130 ( take the square root of both sides )

g = \sqrt{130} ≈ 11.4 feet

7 0
3 years ago
Show workings please
Alenkinab [10]

Answer: x = 21°

Step-by-step explanation:

37 + 4x + (3x - 4) = 180°   Original Equation

37 + 4x + 3x - 4 = 180°   Commutative Property of Addition

7x + 33 = 180°   Combine like terms

7x = 148°  Subtract 33 from both sides

x = 21°   Divide both sides by 7

8 0
3 years ago
Solve for e: (-7) e/3+14
baherus [9]
If the question is supposed to be -7= \frac{e}{3}+14&#10;   Subtract 14 from both sides to get -21=  \frac{e}{3}

Now multiply both sides by 3 to get 3(-21)=-63=e
4 0
3 years ago
Read 2 more answers
The county fair charges $1.25 per ticket for the rides. Jermaine bought 25 tickets for the rides and spent a total of $43.75 at
aniked [119]

Hello Anna,

(a)

1.25 per ticket

? number of rides (x)

43.75 total cost (y)

Admission (z)


(b) Linear Equation - 1.25x + z = y


(c) Well you need to calculate the totaly number of rides that person took and add that to the admission cost.


8 0
3 years ago
An upper triangular matric is square matrix with all zeros below its daignal. A lower triangular matrix is a square matrix with
AleksandrR [38]

Answer:

U₂₁ and U₂₂ fits in the line of upper triangular

Step-by-step explanation:

As explain in the question

An upper triangular matric is square matrix with all zeros below its daignal. A lower triangular matrix is a square matrix with all zeros above its diagonal.

(as shown in the attached image)

(a)for all 3×3 upper triangular matirices U, verify that U2 is also upper triangular

for a matrices U (having a 3*3 matrix), assuming for example, U is given below:

U = \left[\begin{array}{ccc}1&2&3\\0&5&6\\0&0&9\end{array}\right]

the element in the upper triangular are 1,2,3,5,6,9 (U₁₁, U₁₂, U₁₃; , U₂₂, U₂₃, U₂₂)

while lower triangular are 0,0,0, the element in the lower triangular are (U₂₁, U₃₁,U₃₂)

U₂₁ and U₂₂ fits in the line of upper triangular

8 0
3 years ago
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