Which of the following is the measure of QRS
2 answers:
Answer:
The answer is D.90°
Step-by-step explanation:
In this case, every measure has to be defined by three points and the vertex of this measure is in the middle point. The angle that is formed between two rays with the same endpoint is measured in degrees. The extreme points form the rays and the middle point is the vertex.
For example, if we want to know the measure ∠ABC, we have to located the points A, B and C, in the same order. Then the rays are in the same direction that A and C, and vertex will be in the point B (the middle one).
Also, there are some definitions for different range of angle measure. I have attached an image that show some definitions.
Finally, the measure ∠QRS corresponds to a right angle (It has the same notation that in the attached image).
Therefore, the measure ∠QRS is 90°
You might be interested in
Answer:
(t, t -1, t)
Step-by-step explanation:
You have three unknowns but only 2 equations, so you can't really SOLVE this...you can get a solution with a variable still in it (I forget what this is called. I think it refers to infinite many solutions). Here's how it works:
Set up your matrix:
You want to change the number in position 21 (the 2 in the scond row) to a 0 so you have y and z left. Do this by multiplying the top row by -2 then adding it to the second row to get that 2 to become a 0. Multiplying in a -2 to the top row gives you:
Then add, keeping the first row the same and changing the second to reflect the addition:
The second equation is this now:
3y - 3z = -3. Solving for y gives you y = z - 1. Let's let z = t (some random real number that will make the system true. Any number will work. I'll show you at the end. Just bear with me...)
lf z = t, and if y = z - 1, then y = t - 1. So far we have that y = t - 1 and z = t. Now we solve for x:
From the first equation in the original system,
x - 2y + z = 2. Subbing in t - 1 for y and t for z:
x - 2(t - 1) + t = 2. Simplify to get
x - 2t + 2 + t = 2 and x - t = 0, and x = t. So the solution set is (t, t - 1, t). Picking a random value for t of, let's say 2, sub that in and make sure it works. If:
x - 2y + z = 2, then t - 2(t - 1) + t = 2 becomes t - 2t + 2 + t = 2, and with t = 2, 2 - 2(2) + 2 + 2 = 2. Check it: 2 - 4 + 4 = 2 and 2 = 2. You could pick any value for t and it will work.