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3 years ago

Hanna bought 28 roses. She divided them into a number of bunches. Each bunch had 7 roses.

1 answer:

8 0

Its (a) 28 ÷ b = 7 Because When we divide 28 roses in each bunch consisting 7 roses therefore there are 4 bunch of roses therefore the equation (a) satisfy the result and the variable b has value 4.

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Factor the expression below. x3 − 27

Gekata [30.6K]

Well, the formula is: (a-b)(a^2+ab+b^2)therefore the answer would be: (x-3)(x^2+3x+9)hope this helps

4 0

3 years ago

Read 2 more answers

Important guyz.....

dusya [7]

Answer:

When two functions combine in a way that the output of one function becomes the input of the other, the function is a composite function.

Step-by-step explanation:

In mathematics, the composition of a function is a step-wise application. For example, the function f: A→ B & g: B→ C can be composed to form a function that maps x in A to g(f(x)) in C. All sets are non-empty sets. A composite function is denoted by (g o f) (x) = g (f(x)). The notation g o f is read as “g of f”

3 0

2 years ago

A bicycle wheel travels 321 in for each revolution. What is the radius of the wheel

Sliva [168]

Answer:

51.1 ≈ r

Step-by-step explanation:

"A bicycle wheel travels 321 in for each revolution"- means that 321 is the circumference of the wheel that is a circle.

C = 2· π· r

What is the radius of the wheel ?

321 = 2· π· r, divide both sides of the equation by 2 π

(321/2·π) = r , use calculator, solve and round the answer

51.1 ≈ r

4 0

2 years ago

Prove the identity (sina-cosatanb)/(cosa+sinatanb) = tan (a+b)

OLga [1]

Sina - (cosa)(tanb)/cosa + (sina)(tanb)
sina ≡ (tana)(cosa)

(tana)(cosa) - (cosa)(tanb)/cosa + (tana)(cosa)(tanb)
= cosa(tana - tanb)/cosa(1 + tanatanb)
(cosas cancel out)
= (tana - tanb)/(1 + tanatanb) ≡ tan(a-b)

7 0

3 years ago

At the Foremost State Bank the average savings account balance in 2012 was $1900. A random sample of 45 savings account balanes

lakkis [162]

Answer:

The calculated |t| = |-26.517|=26.517 > 2.326 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

Step-by-step explanation:

Step(i):-

Mean of the Population = 1900

Given random sample size 'n' = 45

Mean of the sample x⁻ = 1000

Standard deviation of the sample = 225

Null Hypothesis:-

There is no difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012.

Alternative Hypothesis :-

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

Step(ii):-

Test statistic

$t = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }$

$t = \frac{1000-1900 }{\frac{225}{\sqrt{45} } }$

t = -900 /33.54 = -26.517

|t| = |-26.517|=26.517

Degrees of freedom

γ = n-1 = 45-1 =44

t₍₀.₀₁ , ₄₄₎ = 2.326

The calculated |t| = |-26.517|=26.517 > 2.326 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

4 0

3 years ago