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2 years ago

What is the factored form of 2x^2-7x+6

Mathematics

1 answer:

Xelga [282]2 years ago

6 0

Answer:

(2x - 3)(x - 2).

Step-by-step explanation:

Factor: 2x^2 - 7x + 6

Use the ac method to do this:

Multiply the leading coefficient by the last term:

2 * 6 = 12.

Now we want 2 numbers whose product is 12 and whose sum is -7.

That would be -3 and -4 so we write:

2x^2 -4x - 3x + 6

Now factor by grouping:

= 2x(x - 2) - 3(x -2)

(x - 2) is common to the 2 parts so we have:

(2x - 3)(x- 2).

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Find a value for y for which the expression (1-y)(3-y)(6-y) has each given value

erik [133]

$\\ \tt\Rrightarrow (1-y)(3-y)(6-y)=-70$

$\\ \tt\Rrightarrow -y(1+1)(3+1)(6+1)=-70$

$\\ \tt\Rrightarrow y(2)(4)(7)=70$

$\\ \tt\Rrightarrow y(56)=70$

$\\ \tt\Rrightarrow y=\dfrac{70}{56}$

$\\ \tt\Rrightarrow y=\dfrac{5}{4}$

$\\ \tt\Rrightarrow (1-y)(3-y)(6-y)=120$

$\\ \tt\Rrightarrow -y(1+1)(3+1)(6+1)=120$

$\\ \tt\Rrightarrow -y(2)(4)(7)=120$

$\\ \tt\Rrightarrow 56y=-120$

$\\ \tt\Rrightarrow y=\dfrac{-120}{56}$

$\\ \tt\Rrightarrow y=\dfrac{-15}{7}$

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Please help me, I'm doing a test.

Tju [1.3M]

Answer:

(3,4)

Step-by-step explanation:

first you're going to solve the equation -2x

your equation should now be: $\left \{ {{-2x+3y\\=6} \atop {-2x=2-2y}} \right.$

next you're going to substitute the given value of -2x into the equation $-2x+3y=6$

so your equation should now be: $2-2y+3y=6$

next you're going to solve the equation for y

equation should now be: y=4

than you're going to substitute the given value of y into the equation $-2x=2-2$ × $4$

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your equation should now be: x=3

then the possible solution of the system is the order pair: (x,y)=(3,4)

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