P(7,6), Q(1,6), R(4,2)
We have PQ parallel to the x axis. We'll call that the base,
b = 7 - 1 = 6
The altitude is then the y difference h = 6 - 2 = 4
The area is 
Answer: 12 square units
In general we can use the shoelace formula for the area of any polygon given coordinates. We write the points like this:
(7,6), (1,6), (4,2)
(1,6), (4,2), (7,6)
The area is then half the absolute value of the sum of the cross products:
Answer:
The next number selected should be between 2 and 3 .
Step-by-step explanation:
x. x f(x) g(x)
0 10 17
1 11 19
2 14 21
3 19 23
4 26 25
3.5 22.25 24
<u>2.5 16.25 22</u>
1.5 12.25 20
0.5 10.25 18
We see the pattern that it is increasing with only a unit. The last given data is mid of the last two values that is 3 and 4.
So the next value would be the mid of the next last two values that is 2 and 3 and will be 2.5
Now it is moving in the reverse direction in the same pattern with a difference of a unit.
Answer:
Step-by-step explanation:
add like terms.
simplified it would be 2ab+2xy or 2(ab+xy)
-2x + 7y = 10 ⇒ -2x + 7y = 10
x - 3y = -3 ⇒ <u>-2x + 6y = 6 </u>
y = 4
-2x + 7(4) = 10
-2x + 28 = 10
<u> -28 -28</u>
<u>-2x</u> = <u>-18</u>
-2 -2
x = 9
(x, y) = (9, 4)
Answer:
C: 80
Step-by-step explanation:
Take 600, and subtract it by the values of 200, 95, 65, and 160.
You get $80 left.
Hope this helps!
