You can use substitution and solve y-x=2 for y which is y= x+ 2 and plug it into the y of the other equasion and you get x=5 y=7
<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).
</span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).
</span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.
</span>
<span>I hope this helps! </span>
2:15+2:31=4:46
4:46+1:16=5:62=6:02
6:02+2:56 =8:56pm or 20:56
Answer:
The measurement of AB is 16.25 units.
Step-by-step explanation:
In right triangle ABC, ∠C is a right angle, m∠A = 52° , AC = 10.01, and AB = c.
We need to find the measurement of AB.
∠C is a right angle, it means AB is hypotenuse.
In a right angle triangle,
Hence, the measurement of AB is 16.25 units.
Answer: 68
Step-by-step explanation: Because I am smart
