Weird question.
logically, the only answer that can make sense is a negative one since it is a decreasing slope.
the secant is the average rate of change (and is 1/tangent)
the tangent is the instantaneous rate of change. (1/secant)
we want the first one which is:<span><span><span><span>Δx</span><span>Δy</span></span>=<span><span>Δ weeks</span><span>Δ lbs</span></span>=<span><span>5−0</span><span>137−150</span></span>=<span>5<span>−13</span></span>=−0.3846</span></span>
Answer:
2x^2 + 3x + 4
Step-by-step explanation:
generally, using long division,
(2x^3-3x^2-5x-12)/(x-3) = 2x^2 + 3x + 4
Answer:
<em>14 </em>° <em>;</em> <em>83 </em>°
Step-by-step explanation:
( 14x - 1 )° + ( 2x + 2 )° = 97°
14x - 1 + 2x + 2 = 97
16x = 96
x = 6
m∠BCA = ( 2 × 6 + 2 )° = <em>14 </em>°
m∠ABC = ( 14x - 1 )° = <em>83 </em>°
1.
a
y = 5/2x - 3...slope = 5/2
5x = 2y - 4
2y = 5x + 4
y = 5/2x +2...slope = 5/2
both equation has same slope = 5/2 so the lines are parallel
b.
2x + 8y = -24
8y = -2x - 24
y = -1/4x - 3...slope = -1/4
48y = -12x -144
y = -1/4 -3...slope = -1/4
both equation has same slope = -1/4 so the lines are parallel
c.
2x-7y = -56
7y = 2x +56
y =2/7x + 8...slope = 2/7
7x +2y = 8
2y = -7x + 8
y = -7/2x + 4...slope = -7/2
first equation has slope = 2/7 and 2nd equation has slope = -7/2...so the lines are perpendicular
2.
A. y = 13
B. y = -2/3x - 2/3 ....slope = -2/3
C. 4x-7y = 56
7y = 4x - 56
y = 4/7x - 8 ...slope = 4/7
D.2x - 4y = -10
4y = 2x +10
y = 1/2x + 5/2....slope = 1/2
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A line perpendicular to -3x + 2y = 8
-3x + 2y = 8
2y = 3x +8
y = 3/2 x +4 ....slope = 3/2
This answer is B
.............................................
a line parallel to 2y -x = 2
2y = x +2
y = 1/2x + 1 ...slope = 1/2
This answer is D
..............................
a line perpendicular to x = -13
answer is A. y = 13
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a line parallel to 16x = 28y so
y = 16x/28
y =4/7x ...slope = 4/7
This answer is C
Answer:
(1, -2)
Step-by-step explanation:
I hope that helps :/
