12! = 12x11x10x9x8x7x6x5x4x3x2x1 =479,001,600
3! = 3x2x1 =6
13! = 6,227,020,800
6,227,020,800 x 6 = 37,362,124,800
479,001,600/37,362,124,800=0.0128
Answer:
Step-by-step explanation:
We are given zeros as x=-4, x=-2
so, we can set up function as
Vertex is at (-1,3)
It means that graph passes through point (-1,3)
so, we can plug x=-1 and f(x)=3
and then we can solve for 'a'
we get
now, we can plug it back
and we get
now, we can simplify it
Answer:
5,789
Step-by-step explanation:
I got 5,789 because there are 9 one digit numbers. 1-9 -> 9x1=9. There are 90 two digit numbers. (10-99)-> 90x2=180. There are 900 three digit numbers. (100-999)-> 900x3=2700. There are 725 four digit numbers. (1000-1724)-> 724x4= 2900. Then, I added 9+180+2700+2900=5789.
In conclusion, the total number of digits required in numbering a book that has 1724 pages is 5789.
Answer:
what is the answer
please tell me and explain
The length of that arc is (90/360)·2·π·6 = (1/4)·12·π = 3·π ≈ 9.42 units;
