The best and most correct answer among the choices provided by your question is the second choice or letter B.
Reflection of a horizontal line <span>has the same result as a rotation of 90 degrees clockwise.</span>
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Answer:
Monthly Living Expense = 2375
Monthly Fixed Expense = 1975
Step-by-step explanation:
Let monthly living expense be "x"
and monthly fixed expense be "y"
<u>"monthly living expenses were 400 more than his monthly fixed expenses":</u>
x = 400 + y
<u>"Richard total monthly expenses were 4350":</u>
x + y = 4350
Putting Equation 1 in Equation 2:
(400 + y) + y = 4350
400 + 2y = 4350
2y = 3950
y = 1975
Now, x = 400 + y = 400 + 1975 = 2375
I'll do the first two problems to get you started. All problems shown will use the same formula.
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Problem 4
The formula to use is
C = 100*(B-A)/A
where
A = old value
B = new value
C = percent change
In this case, A = 12 and B = 36, so
C = 100*(B-A)/A
C = 100*(36-12)/12
C = 100*(24/12)
C = 100*2
C = 200%
We have a 200% increase. It is an increase because the value of C is positive.
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Problem 5
Use the same formula as in the previous problem. This time,
A = 75 is the old value
B = 25 is the new value
C = 100*(B-A)/A
C = 100*(25-75)/75
C = 100*(-50/75)
C = 100*(-2/3)
C = -66.6667%
C = -66.7%
The value of C is negative, so we have a percent decrease of roughly 66.7%
Answer:
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The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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