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djverab [1.8K]
2 years ago
7

Explain why the cubed root of -8/27 is -2/3

Mathematics
2 answers:
Len [333]2 years ago
4 0
Help me and I’ll help you
Kazeer [188]2 years ago
4 0

Answer:

Because the cubed root of the numerator and denominator equals the answer

Step-by-step explanation:

alright, we are trying to understand WHY \sqrt[3]{\frac{-8}{27} }  =  -\frac{2}{3}

You can actually rewrite the first number as -\frac{\sqrt[3]{8} }{\sqrt[3]{27} }

you must look for the number, which three times itself, equals 8...

...and the same thing for the bottom: a number, which three times itself... equals 27.

What number cubed equals 8? The answer is 2

What number cubed equals 27? The answer is 3

...so now we have -2 over 3. You can double check this answer.

-\frac{2}{3} * -\frac{2}{3}  = \frac{4}{9}

\frac{4}{9} * -\frac{2}{3} = -\frac{8}{27}

we get the original number that we were looking for the cubed root... SUCCESS.

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(50 points) Which graph is defined by the function given below?
marta [7]

Answer:

Graph B

Step-by-step explanation:

y = (x - 3)(x - 3)

The x intercepts are at 3

Since both intercepts are at 3, the vertex is at 3

We know it is an upwards facing parabola since it is quadratic and the constant out front is positive

5 0
2 years ago
Need help asap, the answer I picked I think is wrong but idk​
BigorU [14]

Answer:

Reflected about the y-axis and then rotated 90° counterclockwise

Step-by-step explanation:

(x , y) to (-x , y) --> reflected over y-axis

then (-x , y)  --> (-y, -x) -->90 degrees rotation counterclockwise

So answer is the last one

Reflected about the y-axis and then rotated 90° counterclockwise

8 0
3 years ago
Determine n between 0 and 19 such that (2311)(3912) ≡ n mod 20.
sleet_krkn [62]

You can write 2311 and 3912 in the form 20q+r:

2311=115\cdot20+11

3912=125\cdot20+12

Then

2311\cdot3912=(115\cdot20+11)(125\cdot20+12)

2311\cdot3912=115\cdot125\cdot20^2+(11\cdot125+12\cdot115)\cdot20+11\cdot12

Taken modulo 20, the terms containing powers of 20 vanish and you're left with

2311\cdot3912\equiv11\cdot12\equiv132\pmod{20}

We further have

132=6\cdot20+12

so we end up with

2311\cdot3912\equiv12\pmod{20}

and so n=12.

###

If instead you're trying to find 2311^{3912}\pmod{20}, you can apply Euler's theorem. We can show that \mathrm{gcd}(2311,20)=1 using the Euclidean algorithm. Then since \varphi(20)=8, and 8 divides 3912, we have

2311^{3912}\equiv2311^{489\cdot8}\equiv(2311^{489})^8\equiv1\pmod{20}

To show 2311 and 20 are coprime:

2311 = 115*20 + 11

20 = 1*11 + 9

11 = 1*9 + 2

9 = 4*2 + 1   =>  gcd(2311, 20) = 1

3 0
3 years ago
Three square flower beds with side of 2m are dug in a rectangular piece of land whose length is 5.2 m and width is 4.8 m. What i
belka [17]

Answer: 12.96 m²

Step-by-step explanation:

The area of the piece of land that the flower beds were dug in is:

= Length * width

= 5.2 * 4.8

= 24.96 m²

The flower beds were 3 in number and all had the shape of a square.

Their area is:

= 3 * (Length * width)

= 3 * ( 2 * 2)

= 3 * 4

= 12 m² for all three flower beds

Remaining land:

= 24.96 - 12

= 12.96 m²

8 0
2 years ago
Which expression is equivalent to 10√5
mixer [17]

Answer:

A. √500

Step-by-step explanation:

Since 500 = 5·100 = 5·10² you can move the 10² out of the √ as 10.

Hence 10√5 = √500

So we're using these rules:

√a·b = √a·√b

and of course

√a² = a  (a>0)

8 0
3 years ago
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