Both lines AB and CD are secant lines beacuse in two points they are touching the circunference. There is a Theorem which says the following
Since the distance from the center of the circle to each secant line is the same (5 units), we could assume that the both secant lines are similar. saying:
Then the lenght of CD is:
I think that the first part is true but the second is wrong because a number and its opposite will have the same absolute value. For example, the 5 is the absolute value of 5 and -5. This works with all numbers and their opposites. Since the number 0 doesn't have an opposite value, I think that 0, as an absolute value, only represents 0.
Hope this helps :P
Answer:
That would be sina.
Step-by-step explanation:
sin(a+b) = sinacosb + cosasinb
sin(a-b) = sinacosb - cosasinb
Adding we get sin(a+b) + sin(a-b) = 2sinaccosb
so sinacosb = 1/2sin(a+b) + sin(a-b)
"The two figures are congruent because rigid motions are used to map Figure 1 onto Figure 2.
"Angle corresponding to ∠J: ∠V
1) Counting the lengths of each side, (by the length of x, and the displacement in y) we can state that both figures are congruent.
Note that this is a rough way of measuring. Just considering the "rise/run" in each line segment.
2) Also, we can state that angle J is corresponding to angle ∠V in figure 2.
3) Thus we can answer that as:
"The two figures are congruent because rigid motions are used to map Figure 1 onto Figure 2.
"Angle corresponding to ∠J: ∠V
Answer:
3.1 x 10^9
Step-by-step explanation:
(2.8 x 10^9) + (3 x 10^8) = (28 x 10^8) + (3 x 10^8)
= (28+3) x 10^8
= 31 x 10^8
= 3.1 X 10^9