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Marat540 [252]
3 years ago
5

There are 20 students In Marks class.Ten percent of the students in Marks homeroom class are also In art class.

Mathematics
1 answer:
poizon [28]3 years ago
4 0

2 students are in art class

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Pleaseeeee help!!!!!<br> Order them least to greatest please
Fiesta28 [93]

Answer and Step-by-step explanation:

\pi is pi, or 3.14159

The absolute value of -4 ( |-4| ) is 4.

These numbers should go in this order:

-10   <   0.121212...   <   \pi   <   |-4|   <   5\frac{1}{2}

<em><u>Have a good day!</u></em>

<em><u></u></em>

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

8 0
2 years ago
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10. rhombus abcd has vertices at a(-2, 7), b(8, 7), c(2, -1), and d (-8, -1).
horrorfan [7]

Answer: 80

Step-by-step explanation:

We can use the formula A=\frac{d_{1}d_{2}}{2}, where d_{1}, d_{2} are the lengths of the diagonals.

By the distance formula,

AC=\sqrt{(-2-2)^{2}+(-1-7)^{2}}=\sqrt{16+64}=4\sqrt{5}\\BD=\sqrt{(-8-8)^{2}+(-1-7)^{2}}=\sqrt{256+64}=8\sqrt{5}

So, the area is \frac{(4\sqrt{5})(8\sqrt{5})}{2}=\boxed{80}

6 0
2 years ago
Quadrilateral ABCD is inscribed in a circle. What is the measure of angle A? Enter your answer in the box.
SashulF [63]

Answer:

135°

Step-by-step Explanation:

==>Given:

An inscribed quadrilateral ABCD with,

m<A = (3x +6)°

m<C = (x + 2)°

==>Required:

measure of angle A

==>Solution:

First, let's find the value of x.

Recall that the opposite angles in any inscribed quadrilateral in a circle are supplementary.

Therefore, this means m<A + m<C = 180°

Thus, (3x+6) + (x+2} = 180

3x + 6 + x + 2 = 180

Collect like terms:

3x + x + 6 + 2 = 180

4x + 8 = 180

Subtract 8 from both sides:

4x + 8 - 8 = 180 - 8

4x = 172

Divide both sides by 4:

4x/4 = 172/4

x = 43

We can now find m<A = (3x + 6)°

m<A = 3(43) + 6

= 129 + 6

measure of angle A = 135°

6 0
3 years ago
If 2^2x = 2^3, what is the value of x?
Advocard [28]

Answer:

x=3/2

Step-by-step explanation:

2^2x=2^3

2x=3

x=3/2

6 0
3 years ago
Given the domain (-2,2,4) what is the range for the relation 3x-y=3
Bumek [7]

Answer:

Given the domain, the range for 3x-y = 3 is {-9, 6, 9}

Step-by-step explanation:

First you have to put the relation in terms of y ⇒ 3x - y = 3⇒ 3x -3 = y

⇒ y = 3x - 3.

Then you replace the values indicated by the domain to find their "y" values (the ones that constitute the range).

f(-2) = -9

f(2) = 6

f(4) = 9.

Finally, the range for the given domain is {-9, 6, 9}

3 0
3 years ago
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